1/8% as a decimal and fraction

Average precipitation for the first 7 months of the year, the average precipitation in toledo, ohio, is 19.32 inches. if the ave

Colt1911 [192]

Part A:

The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\sigma}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

$P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{2.44}\right) \\ \\ =1-P(z\ \textless \ -0.5410) \\ \\ =1-0.29426=\bold{0.7057}$

Part B:

The probability that an n randomly selected samples of a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\frac{\sigma}{\sqrt{n}}}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that 5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:

 $P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{\frac{2.44}{\sqrt{5}}}\right) \\ \\ =1-P(z\ \textless \ -1.210) \\ \\ =1-0.1132=\bold{0.8868}$

7 0

3 years ago

What will the graph look like for a system of equations that has no solution?

lyudmila [28]

Answer:

D

Step-by-step explanation:

The solution to a systems of equations is the intersection point of the lines. If no solution is possible then their is no intersection point. The lines must be parallel.

8 0

3 years ago

Solve for <3 A * 3 = [?] O = 43 44=90°

kap26 [50]

Answer:

90°

Step-by-step explanation:

as a straight line is 180°

and the angle 4 is 90 degrees it must mean that the other side is 90 degrees too

8 0

2 years ago

Please Help! Evaluate the function at each specified value of the independent variable and simplify. (If an answer is undefined,

Licemer1 [7]

Answer:

Given:

g(t) = 5t² − 8t + 3

Find the following

g(2)

g(2) = 5(2²) - 8(2) + 3 = 20 - 16 + 3 = 7

g(t - 2)

g(t - 2) = 5(t - 2)² - 8(t - 2) + 3 = 5t² - 20t + 20 - 8t + 16 + 3 = 5t² - 28t + 39

g(t) - g(2)

g(t) - g(2) = 5t² − 8t + 3 - 7 = 5t² − 8t - 4

3 0

3 years ago

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The mass of the sun is 2.13525×1030 kilograms. The mass of Mercury is 3.285×1023 kilograms. How many times greater is the mass o

Helga [31]

6.5 x 10^6 To answer this question, you need to divide the mass of the sun by the mass of mercury. So 2.13525 x 10^30 / 3.285 x 10^23 = ? To do the division, divide the mantissas in the normal fashion 2.13525 / 3.285 = 0.65 And subtract the exponents. 30 - 23 = 7 So you get 0.65 x 10^7 Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving 6.5 x 10^6 So the sun is 6.5 x 10^6 times as massive as mercury.

8 0

3 years ago

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