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2 years ago

Which solid figure has 4 faces that are triangles and 1 face that is a rectangle? *

Mathematics

1 answer:

victus00 [196]2 years ago

4 0

Answer:

I believe it is a rectangular-based pyramid. Hope this helps :)

Step-by-step explanation:

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Show all work and provide necessary descriptions

masya89 [10]

Let

$P=(P_x,P_y),\quad Q=(Q_x,Q_y)$

If M is the midpoint, the x and y coordinates of M are the average of the x and y coordinates of P and Q:

$M=\left(\dfrac{P_x+Q_x}{2},\ \dfrac{P_y+Q_y}{2}\right)$

We can solve this expression for the coordinates of Q:

$M_x = \dfrac{P_x+Q_x}{2} \implies Q_x = 2M_x-P_x$

$M_y = \dfrac{P_y+Q_y}{2} \implies Q_y = 2M_y-P_y$

Plug in the values for the coordinates of M and P to get

$Q_x = 2M_x-P_x = 2\cdot 5-11 = 10-11=-1$

$Q_y = 2M_y-P_y = 2\cdot (-2) - (-10) = -4+10=6$

5 0

3 years ago

I need to find the image coordinates of the pre-image using reflection, and it has to be reflected over the line x=2. How do I s

Sladkaya [172]

The answer would be ( x+1, y+4)...... Hope this helps

5 0

2 years ago

Round the following numbers to the nearest hundreds place.

Eddi Din [679]

62,900
21,000
126,300
856,700

7 0

3 years ago

Given the right triangle shown below.if Cos A =15/17 and tan A=8/15 which of the following represents the length of BC

otez555 [7]

Answer:

The Figure for Right triangle is below,

Therefore , 15 unit length represents BC.

Step-by-step explanation:

Given:

Consider a right triangle ABC, Such that

$\cos A=\dfrac{15}{17}\\\\\tan A=\dfrac{8}{15}$

To Find:

BC = ?

Solution:

In Right Angle Triangle ABC, Cosine and Tangent identity

$\cos A = \dfrac{\textrm{side adjacent to angle C}}{Hypotenuse}\\$

$\tan A= \dfrac{\textrm{side opposite to angle A}}{\textrm{side adjacent to angle A}}$

BUT,

$\cos A=\dfrac{15}{17}\\\\\tan A=\dfrac{8}{15}$ ....Given

On Comparing,

Adjacent side to angle A = AB = 15

Opposite side to angle A = BC = 8

Hypotenuse = AC =17

Also Pythagoras theorem is Satisfies,

$(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}$

$(\textrm{Hypotenuse})^{2} = 17^{2}=289$

$(\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}=15^{2}+8^{2}=289$

The Figure for Right triangle is below,

Therefore , 15 unit length represents BC.

7 0

3 years ago

What is 6w =30;5,6,7 how is it to be solved?

Gennadij [26K]

6w=30; divide 30 by 6 to the w by itself; the answer is 5

3 0

2 years ago