Answer:
okay i will
Step-by-step explanation:
3 necklaces were sold and they have got 45 revenue
Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
His estimate is reasonable. But only if Michael is less than 2 years old.
Answer:
D.
Step-by-step explanation:
The area is the product of 2 adjacent sides:
Area = (5x - 3y)(5x - 3y) as the sides of a square are all equal.
= 5x(5x - 3y) - 3y(5x - 3y)
= 25x^2 - 15xy - 15xy + 9y^2
= 25x^2 - 30xy + 9y^2.
