2-5|5m-5|=-73 absoute value
2 answers:
You might be interested in
Answer:
(a) 0.0256
(b) 0.2944
Step-by-step explanation:
For solving this exercise we can apply the binomial distribution. The equation that give as the probability is:
Where n is the number of identical events, p is the probability that the event has a success and x is the number of success in the n identical events.
Additionally, nCx is calculated as:
So, in this case we have 2 identical events because we are going to select two people randomly and the probability p of success is the probability that the person is allergic to pollen and this probability is 16%.
Then, for the first case, x is 2 because their are asking for the probability that both are allergic to pollen. Replacing the values of x, n and p we get:
P(2,2,0.16)=0.0256
For the second case, their are asking for the probability that at least one is allergic to pollen, that means that we need to sum the probability that both are allergic to pollen with the probability that just one is allergic to pollen.
Using the same equation to calculate P(1,2,0.16) we get:
P(1,2,0.16)=0.2688
So, the probability that at least one person is allergic to pollen is 0.2944 and it is calculated as:
0.0256 + 0.2688 = 0.2944
Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. At time = 1.25 seconds, the gum is at a maximum height above the ground and 1 second later the gum is on the ground again.
a. If the diameter of the wheel is 68 cm, write an equation that models the height of the gum in centimeters above the ground at any time, t, in seconds.
b. What is the height of the gum when Lamaj gets to the end of the block at t = 15.6 seconds?
c. When are the first and second times the gum reaches a height of 12 cm?
Answer:
Step-by-step explanation:
a)
We are being told that:
Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. This keeps the wheel of his bike in Simple Harmonic Motion and the Trigonometric equation that models the height of the gum in centimeters above the ground at any time, t, in seconds. can be written as:
where;
y = is the height of the gum at a given time (t) seconds
34 = amplitude of the motion
the amplitude of the motion was obtained by finding the middle between the highest and lowest point on the cosine graph.
= the period of the graph
1.25 = maximum vertical height stretched by 1.25 m to the horizontal
b) From the equation derived above;
if we replace t with 1.56 seconds ; we can determine the height of the gum when Lamaj gets to the end of the block .
So;
Thus, the gum is at 58.01 cm from the ground at t = 15.6 seconds.
c)
When are the first and second times the gum reaches a height of 12 cm
This indicates the position of y; so y = 12 cm
From the same equation from (a); we have :
t = 2.72 seconds
Similarly, replacing cosine in the above equation with sine; we have:
t = 2.527 seconds
Hence, the gum will reach 12 cm first at 2.527 sec and second time at 2.72 sec.