Answer:
Step-by-step explanation:
the distance around the figure--we need to find the perimeter
we have rectangle that has the side, 8 and 15
P(r)=2(8)+2(15)=16+30=46
we also have half of the circle with the diameter =8 and r=4
Circumference =2*3.14*r
C=2*3.14*4=25.12
we need just half of the circle 25.12/2=12.56
P figure=46+12.56=58.56
Area= rectangle=l*w=8*15=120
Area(circle)=3.14*r^2=3.14*16=50.24
half circle 50.24/2=25.12
Area figure=120+25.12=145.12
Answer:
The answer would be 300 calories
Step-by-step explanation:
To find the amount of calories in 8 ounces we need to make the ounce amount the same. Let x equal the number of calories.
75/2=x
To get to 8 ounces we need to multiply the bottom by 4. and what we do to the bottom we do to the top.
75*4/2*4=x
multiply
300/8=x
There are 300 calories in 8 ounces.
Answer:
z < ¾
Step-by-step explanation:
Or z < 0.75
...........
If the slopes of the 2 lines are equal then they are parallel.
If m1m2 = -1 (where m1 and m2 are the slopes of the 2 lines) then they are perpendicular.
If the 2 slopes do not match either the first or second conditions then they are neither parallel or perpendicular.
Complete Question:
A population proportion is 0.4. A sample of size 200 will be taken and the sample proportion p will be used to estimate the population proportion. Use z- table Round your answers to four decimal places. Do not round intermediate calculations. a. What is the probability that the sample proportion will be within ±0.03 of the population proportion? b. What is the probability that the sample proportion will be within ±0.08 of the population proportion?
Answer:
A) 0.61351
Step-by-step explanation:
Sample proportion = 0.4
Sample population = 200
A.) proprobaility that sample proportion 'p' is within ±0.03 of population proportion
Statistically:
P(0.4-0.03<p<0.4+0.03)
P[((0.4-0.03)-0.4)/√((0.4)(.6))/200 < z < ((0.4+0.03)-0.4)/√((0.4)(.6))/200
P[-0.03/0.0346410 < z < 0.03/0.0346410
P(−0.866025 < z < 0.866025)
P(z < - 0.8660) - P(z < 0.8660)
0.80675 - 0.19325
= 0.61351
B) proprobaility that sample proportion 'p' is within ±0.08 of population proportion
Statistically:
P(0.4-0.08<p<0.4+0.08)
P[((0.4-0.08)-0.4)/√((0.4)(.6))/200 < z < ((0.4+0.08)-0.4)/√((0.4)(.6))/200
P[-0.08/0.0346410 < z < 0.08/0.0346410
P(−2.3094 < z < 2.3094)
P(z < -2.3094 ) - P(z < 2.3094)
0.98954 - 0.010461
= 0.97908
