Answer:
Mailing preparation takes 38.29 min max time to prepare the mails.
Step-by-step explanation:
Given:
Mean:35 min
standard deviation:2 min
and 95% confidence interval.
To Find:
In normal distribution mailing preparation time taken less than.
i.eP(t<x)=?
Solution:
Here t -time and x -required time
mean time 35 min
5 % will not have true mean value . with 95 % confidence.
Question is asked as ,preparation takes less than time means what is max time that preparation will take to prepare mails.
No mail take more time than that time .
by Z-score or by confidence interval is
Z=(X-mean)/standard deviation.
Z=1.96 at 95 % confidence interval.
1.96=(X-35)/2
3.92=(x-35)
X=38.29 min
or
Confidence interval =35±Z*standard deviation
=35±1.96*2
=35±3.92
=38.29 or 31.71 min
But we require the max time i.e 38.29 min
And by observation we can also conclude the max time from options as 38.29 min.
Answer:
12 ....10....11....13 THATS THE CORRECT ORDER
Step-by-step explanation:
Step-by-step explanation:
We need to show whether

or

so we'll do either one of them,
we'll convert f(x) to f^-1(x) and lets see if it looks like g(x).

we can also write it as:

now all we have to do is to make x the subject of the equation.



now we'll interchange the variables

this is the inverse of f(x)

and it does equal to g(x)

Hence, both functions are inverse of each other!
This can be shown graphically too:
we can see that both functions are reflections of each other about the line y=x.
Answer:
Step-by-step explanation:
-2.67
7/10
2.67
2.07,2
Answer:
- D. It is a many-to-one function
Step-by-step explanation:
- One-t<em>o-one if every y value has exactly one x value mapped onto it</em>
- <em>Many-to-one if there are y values that have more than one x value mapped onto them.</em>
We have a function that is of degree 3, so it has 3 x-intercepts which means there are points (x₁, 0), (x₂, 0), (x₃, 0), so it is a many-to-one function
Correct option is D