<span>Area is base times height, so 9h = 36, h = 4
sine of base angle will be 4/6 = 2/3
So, the answer is A) 2/3
Hope this helps!
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If sin Ф=1/3>0 and tan Ф<0; then Ф belongs to the second quadrant and cos Ф will be negative (cos Ф<0).
sin²Ф+cos²Ф=1
(1/3)²+cos²Ф=1
1/9+cos²Ф=1
cos²Ф=1-1/9
cos²Ф=8/9
cos Ф=⁺₋√(8/9)=⁺₋2√2 / 3
We have two possible solutions.
cos Ф=2√2 / 3 This solutions is not possible, because in this case cos Ф has to be negative (cos Ф<0)
cos Ф=(-2√2) / 3 this solutions is right.
answer:B. -2 square root 2 /3 (or (-2√2) /3 )
No you would not have enough flour because if you add those to mixed numbers together you would get 4 and 1/12
We must find UNIQUE combinations because choosing a,b,c,d... is the same as d,c,b,a...etc. For this type of problem you use the "n choose k" formula...
n!/(k!(n-k)!), n=total number of choices available, k=number of choices made..
In this case:
20!/(10!(20-10)!)
20!/(10!*10!)
184756
