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Angelina_Jolie [31]
3 years ago
12

Part A: Solve −np − 80 < 60 for n. Show your work. (4 points)

Mathematics
2 answers:
Alika [10]3 years ago
5 0

Answer:

<em>Part A ⇒ n>-140/p and p≠0  </em>

<em>Part B. ⇒ d=-30-2a/5</em>

Step-by-step explanation:

<em>Part A. -np-80<60</em>

<em>First, add by 80 both sides of equation.</em>

<em>-np-80+80<60+80</em>

<em>Simplify.</em>

<em>60+80=140</em>

<em>-np<140</em>

<em>Then, multiply by -1 both sides of equation.</em>

<em>(-np)(-1)>140(-1)</em>

<em>Simplify.</em>

<em>np>-140</em>

<em>Divide by p both sides of equation.</em>

<em>np/p>-140/p; p≠0</em>

<em>Simplify to find the answer.</em>

<em>n>-140/p; p≠0 is the correct answer from part a.</em>

<em>___________________________________</em>

Part B. 2a-5d=30

<em>First add by 2a from both sides of equation.</em>

<em>2a-5d+2a=30+2a</em>

<em>Then, simplify.</em>

<em>-5d=30-2a</em>

<em>Divide by -5 from both sides of equation.</em>

<em>-5d/-5=30/-5-2a/5</em>

<em>Simplify, to find the answer.</em>

<em>d=-30-2a/5 is the correct answer from part b.</em>

UkoKoshka [18]3 years ago
5 0

Part A:

For this case we have the following inequality:

-np-80

We add 80 to both sides of the inequality:

-np

Dividing between -p on both sides, having to change the inequality sign:

n> - \frac {140} {p}

Part B:

For this case we have the following equation:

2a-5d = 30

Subtracting 2a on both sides:

-5d = 30-2a

Dividing between -5 on both sides:

d = \frac {30-2a} {- 5}\\d = \frac {-30+2a} {5}\\d = - \frac {30} {5} +\frac {2a} {5}\\d = -6+ \frac {2a} {5}

Answer:

n> - \frac {140} {p}\\d = -6+\frac {2a} {5}

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