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earnstyle [38]
3 years ago
6

Are there any outliers in the data?

Mathematics
2 answers:
Marianna [84]3 years ago
7 0

Answer:

Yes

Step-by-step explanation:

30 is an outlier because it is much different from the other data points.

Burka [1]3 years ago
3 0

Answer:

yes, there are a few outliers

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given the arithemtic or geometric sequence, identify f(0) and the common difference ratio f(x) = 4-2/3x
ankoles [38]

<u>Answer: </u>

Required value of f(0) = 4 and common difference of given sequence is \frac{-2}{3}

<u>Solution: </u>

Given sequence rule for arithmetic sequence is  \mathrm{f}(\mathrm{x})=4-\left(\frac{2}{3}\right) x

We need to determine f(0) and common difference

Calculating f(0).

Substituting x = 0 in given sequence rule  we get

\begin{array}{l}{f(0)=4-\left(\frac{2}{3}\right) 0} \\ {=4-0=4}\end{array}

Calculating common difference  

Let’s first calculate f(1) and f(2).

Substituting x = 1 in given sequence rule  

\begin{array}{l}{\mathrm{f}(1)=4-\left(\frac{2}{3}\right) 1} \\ {=4-\left(\frac{2}{3}\right)=\frac{10}{3}}\end{array}

\mathrm{f}(2)=4-\left(\frac{2}{3}\right) 2=4-\left(\frac{4}{3}\right)=\frac{8}{3}

Common Difference can be found by subtracting f(1) from f(2)

\text { Common difference }=\mathrm{f}(2)-\mathrm{f}(1)=\left(\frac{8}{3}\right)-\left(\frac{10}{3}\right)=\frac{-2}{3}

Hence required value of f(0) = 4 and common difference of given sequence is \frac{-2}{3}

7 0
2 years ago
You invested $27,200 and started a business selling vases. Supplies cost $11 per
AleksAgata [21]
1,600 vases must be produced and sold to break even.

x($28-$11)=$27,200
Simplify to 17x=27,200
Divide 17x by 17 so it cancels out.
What you do to one side of the equation you have to do to the other.
27,200/17=1,600
x=1,600
6 0
2 years ago
(1/27)^x-6=27<br><br>Could I please have a step by step as well? Much appreciated! ​
Andrei [34K]

Answer:

x = 7

Step-by-step explanation:

1) Use Division Distributive Property: (x/y)^a = x^a/y^a.

\frac{1}{ {27}^{x - 8} }  = 27

2) Multiply both sides by 27^x - 8.

1 =  {27} \times 27^{1 + x  - 8}

3) Use the product rule: x^a x^b = x^a+b.

1 =  {27}^{1 + x - 8}

4) Simplify 1 + x - 8 to x - 7.

1  =  {27}^{x - 7}

5) Use Definition of Common Logarithm: b^a = x if and only if log<u>b</u><u> </u>(x) = a.

log_{27}1 = x - 7

6) Use Change of Base Rule.

\frac{ log_1  }{  log{27} }  = x - 7

7) Use rule of 1: log 1 = 0.

\frac{0}{ log_{27}}  = x - 7

8) Simplify 0/log_27 to 0.

0 = x - 7

9) Add 7 to both sides.

7 = x

10) Switch sides.

x = 7

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>7</u><u>.</u>

5 0
3 years ago
Ethan invested £500 in the bank for 2 years.
Anon25 [30]

Answer:

Step-by-step explanation:

I=PRT/100

40=(500XRX2)/100

R=(40X100)/500X2

R=4000/1000

R=4 percent/annum

3 0
3 years ago
Cathrine has £7000 to invest.
Anvisha [2.4K]
Since this is a compound interest problem, you have to take note that the amount Catherine will get per year is not the same. It will increase per year since it is compounded. So first, we get the amount after one year. This will be 7000 x 0.04 which is 280 plus 7280. In the second year, she will get 7571 (7280 x 0.04 + 7280). In the third year, she will get 7874 (7571 x 0.04 + 7571). In the fourth year, she will get 8189 (7874 x 0.04 + 7874). And finally in the fifth year, she will get 8517 (8189 x 0.04 +8189). So after five years, she has 8517
4 0
3 years ago
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