All categories

2 years ago

I don’t understand this do any of you do?

Mathematics

1 answer:

strojnjashka [21]2 years ago

8 0

Answer:

a reflection across line y, then a translation (1,-5) (right 1, down 5)

Step-by-step explanation:

A(-2,4) → (2, 4) → D(3, -1)

B(-6, 1) → (6, 1) → E(7, -4)

C(-3, 1) → (3, 1) → F(4, -4)

You might be interested in

it takes a lady 26 minutes to travel 3 km by walking the first part at 6 km per hour and running the second part at 10 km per ho

Natasha2012 [34]

Answer:

78 meter 360meters 600 meters

3 0

2 years ago

In a student government election, 6 seniors, 2 juniors, and 3 sophomores are running for election. Students elect four at-large

Harrizon [31]

4-0-0
2-1-1
1-2-1
1-0-3
0-1-3

Those are just the ones I can think of so about 5 ways

3 0

2 years ago

Read 2 more answers

Answer needed ASAP !!!!

kumpel [21]

Answer:

The answer is C)

Step-by-step explanation:

if you graph it on desmos they are the same line.

6 0

2 years ago

Read 2 more answers

-27+ 18-(10-14)-(12)

vladimir2022 [97]

Answer:

-27 + 18 + 4 - 12

-9 + 4 - 12

-5 - 12 =-17

3 0

3 years ago

Can anyone explain how to do mathematical induction. The question is below. Brainliest awarded for the right answer. Thanks.

igomit [66]

The sum of the triangular numbers is $\frac{n(n+1)(n+2)}{6}$

According to the question, the series of triangular numbers is given as in the form of the number of dots constituting the equilateral triangles i.e.
1, 3, 6, 10, 15 . . . . .n

<h3>what is triangular numbers?</h3>

triangular number are the sequence and series of the numbers and each number represents and constitute in visualization of series of equilateral triangle.

given series in the figure
1, 3, 6, 10, 15, . . . . . . ., n
each number represents the number of dots containing in triangle
now the series can be given by
$S = \frac{n(n+1)}{2}$ for n = 1, 2, 3, 4,. . . . .n
now , according to the question the sum of the series can be given as
⇒ ∑S
⇒ ∑ $\frac{n^2+n}{2}$
⇒ $\frac{1}{2}[\sum n^2+\sum n]\\\frac{1}{2}[\frac{n(n+1)(2n+1)}{6}+\frac{n(n+1)}{2}] \\\frac{n(n+1)}{4}[\frac{(2n+1)}{3}+1] \\\frac{n(n+1)}{4}[\frac{(2n+1+3)}{3}] \\\frac{n(n+1)}{4}[\frac{(2n+4)}{3}] \\\frac{n(n+1)}{4}2[\frac{(n+2)}{3}]\\\frac{n(n+1)(n+2)}{6}$

Thus, the sum of the triangular number is given by $\frac{n(n+1)(n+2)}{6}$

Learn more about triangular numbers here:
brainly.com/question/1417765

#SPJ1

3 0

2 years ago