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diamong [38]
3 years ago
14

I don’t understand this do any of you do?

Mathematics
1 answer:
strojnjashka [21]3 years ago
8 0

Answer:

a reflection across line y, then a translation (1,-5) (right 1, down 5)

Step-by-step explanation:

A(-2,4) → (2, 4) → D(3, -1)

B(-6, 1) → (6, 1) → E(7, -4)

C(-3, 1) → (3, 1) →  F(4, -4)

You might be interested in
Find the distance between the points c ( 6, 5) and D(-3, 1),
svet-max [94.6K]

Answer:

see explanation

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (6, 5) and (x₂, y₂ ) = (- 3, 1)

d = \sqrt{(-3-6)^2+(1-5)^2}

  = \sqrt{(-9)^2+(-4)^2}

  = \sqrt{81+16}

  = \sqrt{97} ≈ 9.85 ( to 2 dec. places )

4 0
2 years ago
5 1/2+ 3 2/3+ 1 4/5
Mazyrski [523]

Answer:

10\frac{29}{30}

Step-by-step explanation:

5\frac{1}{2} +3\frac{2}{3} +1\frac{4}{5}

Let us group the integers and the fractions.

5\frac{1}{2} +3\frac{2}{3} +1\frac{4}{5} = (5+3+1)+(\frac{1}{2} +\frac{2}{3}+\frac{4}{5}  )

= 9+\frac{15+20+24}{30}

= 9+\frac{59}{30}

=9+1\frac{29}{30}

=10\frac{29}{30}

7 0
3 years ago
I NEED HELP ASAP PLEASE
11Alexandr11 [23.1K]
The answr is 2 okay that’s the answer
8 0
1 year ago
The width of a rectangle is 5 more than twice the length. If the perimeter of the rectangle is 190 meters ,what is the width of
slega [8]
P=2(l+w)

190=2[(2l+5)+l)
190=4l+10+2l
190=6l+10
180=6l
l=30

190=2(30+w)
190=60+2w
130=2w
w=65

The width of the rectangle is 65.
6 0
3 years ago
T/2 = 9? i need help
PtichkaEL [24]

Answer:

18/2 =9

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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