Parameterize
by

with
and
. Take a normal vector to
,

which has norm

Then the integral of
over
is


Answer:

Step-by-step explanation:
Line g passes through (-2,6) and (-3,2).
The slope of line g is given by:

Let's substitute the values to get:

The equation that is perpendicular to line g will have a slope that is the negative reciprocal of 4.
i.e -1/4
If this line passes through (P,Q), then the equation is:

Answer:
1250 p² x¹² y³z⁶m⁵
Step-by-step explanation:
5x²y³z⁵m²(-2p²m³zx⁴)(-5x²)³
5x²y³z⁵m²(-2p²m³zx⁴)(-125x⁶)
5x²y³z⁵m²(250p²m³zx¹⁰)
1250 p²x¹²y³z⁶m⁵
Answer:
x = 10
Explanation:
Note the following rules before we begin:
2 ln(a) = ln (a²)
ln (a) + ln (b) = ln (ab)
Now, for the given:
ln(20) + ln(5) = 2 ln(x)
ln(20*5) = ln(x²)
ln(100) = ln(x²)
This means that:
100 = x²
Therefore:
either x = 10 .........> acceped
or x = -10 .........> rejected as no negatives are allowed within ln functions
Hope this helps :)
Let change 7/8 and 1/5 into decimal point so 0.88 and 0.2
0.88-0.2 =0.68
then we want 5 equal length so we divided
0.68 / 5 =0.14