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3 years ago

I don’t understand this do any of you do?

Mathematics

1 answer:

strojnjashka [21]3 years ago

8 0

Answer:

a reflection across line y, then a translation (1,-5) (right 1, down 5)

Step-by-step explanation:

A(-2,4) → (2, 4) → D(3, -1)

B(-6, 1) → (6, 1) → E(7, -4)

C(-3, 1) → (3, 1) → F(4, -4)

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Find the distance between the points c ( 6, 5) and D(-3, 1),

svet-max [94.6K]

Answer:

see explanation

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (6, 5) and (x₂, y₂ ) = (- 3, 1)

d = $\sqrt{(-3-6)^2+(1-5)^2}$

= $\sqrt{(-9)^2+(-4)^2}$

= $\sqrt{81+16}$

= $\sqrt{97}$ ≈ 9.85 ( to 2 dec. places )

4 0

2 years ago

5 1/2+ 3 2/3+ 1 4/5

Mazyrski [523]

Answer:

$10\frac{29}{30}$

Step-by-step explanation:

$5\frac{1}{2} +3\frac{2}{3} +1\frac{4}{5}$

Let us group the integers and the fractions.

$5\frac{1}{2} +3\frac{2}{3} +1\frac{4}{5}$ = $(5+3+1)+(\frac{1}{2} +\frac{2}{3}+\frac{4}{5} )$

= $9+\frac{15+20+24}{30}$

$= 9+\frac{59}{30}$

$=9+1\frac{29}{30}$

$=10\frac{29}{30}$

7 0

3 years ago

I NEED HELP ASAP PLEASE

11Alexandr11 [23.1K]

The answr is 2 okay that’s the answer

8 0

1 year ago

The width of a rectangle is 5 more than twice the length. If the perimeter of the rectangle is 190 meters ,what is the width of

slega [8]

P=2(l+w)

190=2[(2l+5)+l)
190=4l+10+2l
190=6l+10
180=6l
l=30

190=2(30+w)
190=60+2w
130=2w
w=65

The width of the rectangle is 65.

6 0

3 years ago

T/2 = 9? i need help

PtichkaEL [24]

Answer:

18/2 =9

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers