NEED HELP <br> what is the range?<br> |80

zhenek [66]

The first fraction is 4 over 6, right? hopefully it is, i cant really see.
Basically, you can divide 4 and 6 by the same number, they have factors in common. They're both multiples of 2. if you divide them both by 2, you get 2 over 3, which is the <em>exact same amount as 4 over 6, it's just written in a simpler way. </em>the first answer is 2 over 3.

What numbers can both 10 and 15 be divided by? give it a try.

4 0

3 years ago

Read 2 more answers

FREEE POINTSSSSSS.....................<br>

Mekhanik [1.2K]

Grabbing dem points up ✨YeAh✨

5 0

3 years ago

Read 2 more answers

The booster club will sell raffle tickets to raise money for new band uniforms. The total cost of the uniforms is $16,272. Each

Zina [86]

Answer: 1,356 tickets

12x=16,272

divide by 12 on both sides

12x÷12=16,272÷12

x=16,272÷12

x=1,356

I hope this is good enough:

7 0

2 years ago

12.

shtirl [24]

B. if u have wdgenuity it’s B i took the test

3 0

2 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

$2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours$

Writing the equation:

$264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph$

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

$SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph$

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

Have a nice day!

7 0

3 years ago

NEED HELP what is the range? |80 - 5x| = 4