Species A: 18.9 miles / 42 minutes = 0.45 miles per minute
Species B: 20.3 miles / 58 minutes = 0.35 miles per minute
Therefore, species A is faster and flies at a speed of 0.45 miles per minute
(27 mph)
0.45 x 60 = 27 mph
Answer:
the slope of both lines are the same.
Step-by-step explanation:
Given the following segment of the Quadrilateral EFGH on a coordinate Segment FG is on the line 3x − y = −2,
segment EH is on the 3x − y = −6.
To determine their relationship, we can find the slope of the lines
For line FG: 3x - y = -2
Rewrite in standard form y = mx+c
-y = -3x - 2
Multiply through by-1
y = 3x + 2
Compare
mx = 3x
m = 3
The slope of the line segment FG is 3
For line EH: 3x - y = -6
Rewrite in standard form y = mx+c
-y = -3x - 6
Multiply through by-1
y = 3x + 6
Compare
mx = 3x
m = 3
The slope of the line segment EH is 3
Hence the statement that proves their relationship is that the slope of both lines are the same.
Answer:
Step-by-step explanation:
Let the number is in the form of xyz
<h3>We have</h3>
Sum of the digits is 19
The second digit is one more than the first digit
The third digit is two more than the second digit
- z = y + 2 = x + 1 + 2 = x + 3
<u>Substitute the values of y and z</u> into the first equation and solve for x
- x + x + 1 + x + 3 = 19
- 3x + 4 = 19
- 3x = 15
- x = 5
<u>Find the value of y and z</u>
- y = 5 + 1 = 6
- z = 5 + 3 = 8
The number is 568
1 1/5 - 1/3
6/5-1/3
18/15-5/15
13/15 is your answer.
I think the person on top got you with the answer
