Answer:
The required answer is 
.
Step-by-step explanation:
Consider the provided numbers:
We need to subtract in base 4.
The place value of 201 is:
1 is at units place, 0 is at four's place and 2 is at 4 squared place.
The place value of 32 is:
2 is at units place and 3 is at four's place.
201
- 32
Start subtracting the numbers from the unit place.
Here, we need to subtract 2 from 1, which is not possible so borrow 4 from the four's place but there is 0 at four's place so borrow from 4 squared place and change 2 to 1.
Also change 0 to 4 because we have borrow 4 from squared place.
Now 1 can borrow 4 from the four's place which will become 1+4=5 and change 4 at four's place to 3.
Now the number will look like this:
135
- 32
Now subtract the number as shown.
135
<u>- 32</u>
103
Hence, the required answer is .
Answer:
it let me now!!
Step-by-step explanation:
so i cant put an answer for some reason but here it is: when dividing fractions you would need to multiply to solve. The easyist way to do so from the ways i learned is keep change flip. so keep: 2/3 change a divide to a multiplication simbol and flip 1/4 to 4/1 so your left with G: 2/3 x 4/1
hope that helps btw if you need me to explain more let me know whats confusing you so i can help!!
Answer:
x < −
5
The notation would be (
−
∞
, −
5
)
On the graph, you would put an open dot on -5 and an arrow continuing down it
Answer: n = 600.25 ≈ 601 ( sample size)
the minimum sample size of the adults in United State who have sleep deprivation is 601
Step-by-step explanation:
Given that;
the confidence level = 95% = 0.05
the Margin of error E = 4% = 0.04
∴ level of significance ∝ = 1 - C.L
∝ = 1 - (95/100)
= 0.05
Z∝/2 = 0.05/2 = 0.025
Z-critical value at 95% confidence level is OR level of significance at 0.025 = 1.96 (z-table)
Now to calculate the sample size, we say
n = (Z(critical) / M.E )² P ( 1 - P)
now we substitute
n = (1.96 / 0.04)² × 0.5 ( 1 - 0.5)
n = 2401 × 0.5 × 0.5
n = 600.25 ≈ 601
Therefore the minimum sample size of the adults in United State who have sleep deprivation is 601
