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Ivanshal [37]
3 years ago
5

The problems in this lesson review basic arithmetic skills.

Mathematics
1 answer:
gladu [14]3 years ago
3 0

Answer:

false

Step-by-step explanation:

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I need help with this math ​
ryzh [129]

Answer:

Right angle

Step-by-step explanation:  you take the 57% angle and ad that with

the 33% angle and you got a prefect 90% also known as a "Right angle"

6 0
3 years ago
First person to answer<br> {15 x 17 x 45} + {76 x 54<br> gets crown
elena-14-01-66 [18.8K]

Step-by-step explanation:

Hey.. Use a calc dude

5 0
2 years ago
Read 2 more answers
X-3=19<br> solve for the variable X<br><br> please show your work<br><br> thx :)
AnnZ [28]
X-3--19
3,6,9,12,15,18
And they don’t have a 19
8 0
3 years ago
Read 2 more answers
The population of a city is 270​,000 and is increasing at a rate of 2.25​% each year. Approximately when will the population rea
maks197457 [2]

The population will reach 540 000 in 30.8 yr.

The formula for population growth is

<em>P</em>_<em>t</em> = <em>P</em>_0 × e^(<em>rt</em>)

540 000 = 270 000 × e^(0.0225t)

e^(0.0225t) = 2

0.0225t = ln2

t = (ln2)/0.0225 = 30.8



8 0
3 years ago
Explain how to find each root, with its multiplicity, for the polynomial y=x^5-27x^2.
Nuetrik [128]

The roots of y = x^{5}-27\cdot x^{2} are 0 (multiplicity 2), -3 (multiplicity 1), -\frac{3}{2}+i\,\frac{3\sqrt{3}}{2} (multiplicity 1) and -\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} (multiplicity 1).

The characteristics of the polynomial can be derived from algebraic techniques. Roots and multiplicity can be found by <em>factoring</em> the polynomial. The multiplicity is represented by a power binomial of the form:

(x-r_{i})^{m},\,m \le n (1)

Where n is the grade of the polynomial.

Now we proceed to factor the formula:

y = x^{5}-27\cdot x^{2}

y = x^{2}\cdot (x^{3}-27)

y = x^{2}\cdot (x^{2}+3\cdot x +9)\cdot (x-3)

Please notice that x^{2}+3\cdot x + 9 have two complex roots.

y = x^{2}\cdot \left(x+\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}  \right)\cdot \left(x+\frac{3}{2}+i\,\frac{3\sqrt{3}}{3}  \right)\cdot (x-3)

The roots of y = x^{5}-27\cdot x^{2} are 0 (multiplicity 2), -3 (multiplicity 1), -\frac{3}{2}+i\,\frac{3\sqrt{3}}{2} (multiplicity 1) and -\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} (multiplicity 1).

We kindly invite to see this question on polynomials: brainly.com/question/1218505

7 0
2 years ago
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