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Ivanshal [37]
3 years ago
5

The problems in this lesson review basic arithmetic skills.

Mathematics
1 answer:
gladu [14]3 years ago
3 0

Answer:

false

Step-by-step explanation:

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Show that 5(3y-2)=15y-10 for at least 5 values of y
Vsevolod [243]
<span>Solving the equation for Y = 1. 5 * (3 * 1 - 2) = 15 * 1 - 10 5 * (3 - 2) = 15 -10 5 * 1 = 5 5 = 5 Solving the equation for Y = 2. 5 * (3 * 2 - 2) = 15 * 2 - 10 5 * (6 - 2) = 30 -10 5 * 4 = 20 20 = 20 Solving the equation for Y = 4. 5 * (3 * 4 - 2) = 15 * 4 - 10 5 * (12 - 2) = 60 -10 5 * 10 = 50 50 = 50 Solving the equation for Y = 8. 5 * (3 * 8 - 2) = 15 * 8 - 10 5 * (24 - 2) = 120 -10 5 * 22 = 110 110 = 110 Solving the equation for Y = 9. 5 * (3 * 9 - 2) = 15 * 9 - 10 5 * (27 - 2) = 135 -10 5 * 25 = 125 125 = 125 This proves that the equation holds good for at least 5 values of 'y', which are 1, 2, 4, 8 and 9. However, it can be proved that the equation holds good for any value of y. Expression 5(3y-2) can be simplified to 15y -10 which is the same expression on the right had side of the equation provided. So, equation 5(3y-2)=15y-10 is actually 15y-10=15y-10 and since this is true for all values of y, it has been proved that it is true for at least 5 values of y.</span>
7 0
3 years ago
Enter the exponential expression as a decimal 10^3​
ollegr [7]
0.001

Step- by-step explanation









4 0
3 years ago
Read 2 more answers
One difference between an assembly line process flow and a continuous process flow is that on the assembly line the flow is disc
IgorLugansk [536]

Answer:

True

Step-by-step explanation:

Assemble line is a production process in which parts are joined to the products produced as a partially finished product.

Here the process flow is discreet that is assembled one at a time.

Continous process flow is a type of manufacturing products without disruption of the flow process.

As the name implies,it is continous.

6 0
3 years ago
What is the equation of this line? Picture included
enot [183]
A straight line needs two pieces of information to be identified, a gradient and a y-intercept (technically any point will do but the y-intercept is particularly convenient if we have it).

The gradient is calculated by taking two points on the line, and dividing the change in y-coordinate by the change in x-coordinate between them. I'm going to take the points (0,-3) and (2,-2).

The change in y-coordinate is (-2) - (-3) = 1

The change in x-coordinate is (2) - (0) = 2.

Gradient = m = 1/2

Next we identify the y-intercept, the value of y when x = 0. This value is -3, and we call it c.

The equation of a line in slope-intercept form is y = mx + c. Slotting in the values for m and c we have ascertained, we find that the equation of this line is:

y = (1/2)x - 3

I hope this helps :)
7 0
3 years ago
An expression is shown below:
Alex73 [517]

Given:

The given expression is:

6x^2y-3xy-24xy^2+12y^2

To find:

Part A: The expression by factoring out the greatest common factor.

Part B: Factor the entire expression completely.

Solution:

Part A:

We have,

6x^2y-3xy-24xy^2+12y^2

Taking out the highest common factor 3y, we get

=3y(2x^2-x-8xy+4y)

Therefore, the required expression is 3y(2x^2-x-8xy+4y).

Part B:

From part A, we have,

3y(2x^2-x-8xy+4y)

By grouping method, we get

=3y(x(2x-1)-4y(2x-1))

=3y(x-4y)(2x-1)

Therefore, the required factored form of the given expression is 3y(x-4y)(2x-1).

3 0
3 years ago
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