Answer:
ferferferferferferf
Step-by-step explanation:
Complete question :
The birthweight of newborn babies is Normally distributed with a mean of 3.96 kg and a standard deviation of 0.53 kg. Find the probability that an SRS of 36 babies will have an average birthweight of over 3.9 kg. Write your answer as a decimal. Round your answer to two places after the decimal
Answer:
0.75151
Step-by-step explanation:
Given that :
Mean weight (m) = 3.96kg
Standard deviation (σ) = 0.53kg
Sample size (n) = 36
Probability of average weight over 3.9
P(x > 3.9)
Using the z relation :
Zscore = (x - m) / (σ / √n)
Zscore = (3.9 - 3.96) / (0.53 / √36)
Zscore = - 0.06 / 0.0883333
Zscore = −0.679245
Using the Z probability calculator :
P(Z > - 0.679245) = 0.75151
= 0.75151
For this case we have the following function:
y = 9 (3) ^ x
Applying the following transformations we have:
Horizontal translations
Suppose that h> 0
To graph y = f (x-h), move the graph of h units to the right.
y = 9 (3) ^ (x-2)
Vertical translations
Suppose that k> 0
To graph y = f (x) -k, move the graph of k units down.
y = 9 (3) ^ (x-2) - 6
Answer:
2 units to the right
6 units down
It would be a combustion reaction
Answer:
x = 4 ± ![\sqrt{19}](https://tex.z-dn.net/?f=%5Csqrt%7B19%7D)
Step-by-step explanation:
Given
x² - 8x = 3
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 4)x + 16 = 3 + 16
(x - 4)² = 19 ( take the square root of both sides )
x - 4 = ±
( add 4 to both sides )
x = 4 ±