2x+4=10
2x=6
x=3
2(3)+4= 10
(plus, on parallelograms like that, parallel sides are equal to each other)
A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
Answer:
AB=AC, BD is shared side, angle 1 and angle 2 are equal as BD bisects angle ABC
So we have two sides and included angle equal.
- <em>If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.</em>
According to the rule above we can say triangles ΔABD ≅ ΔCBD
Square root of 5, 2 1/2, square root of 7, pi, square root of 11, 3.5.
