All categories

2 years ago

Please help . I’ll mark you as brainliest if correct!!!

Mathematics

1 answer:

damaskus [11]2 years ago

8 0

Answer:10 Seconds

Step-by-step explanation:

s=1600 ft

t=√(s) /4

t=√(1600)/4

t=40/4

t=10 seconds

You might be interested in

Which point would be a solution to the system of linear inequalities ?

brilliants [131]

Answer:

(12,-6)

Step-by-step explanation:

we have

$y\leq \frac{4}{3}x+5$ ----> inequality A

$y\geq -\frac{5}{2}x+5$ ---> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

<u><em>Verify each point</em></u>

Substitute the value of x and the value of y of each ordered pair in the inequality A and in the inequality B

case 1) (0,-1)

Inequality A

$-1\leq \frac{4}{3}(0)+5$

$-1\leq5$ ----> is true

Inequality B

$-1\geq -\frac{5}{2}(0)+5$

$-1\geq 5$ ----> is not true

therefore

The ordered pair is not a solution of the system

case 2) (0,3)

Inequality A

$3\leq \frac{4}{3}(0)+5$

$3\leq5$ ----> is true

Inequality B

$3\geq -\frac{5}{2}(0)+5$

$3\geq 5$ ----> is not true

therefore

The ordered pair is not a solution of the system

case 3) (-6,-6)

Inequality A

$-6\leq \frac{4}{3}(-6)+5$

$-6\leq-3$ ----> is true

Inequality B

$-6\geq -\frac{5}{2}(-6)+5$

$-6\geq 20$ ----> is not true

therefore

The ordered pair is not a solution of the system

case 4) (12,-6)

Inequality A

$-6\leq \frac{4}{3}(12)+5$

$-6\leq21$ ----> is true

Inequality B

$-6\geq -\frac{5}{2}(12)+5$

$-6\geq -25$ ----> is true

therefore

The ordered pair is a solution of the system (makes true both inequalities)

8 0

3 years ago

An engineer is designing a storage compartment in a spacecraft .The compartment must be 2 meters longer than it is wide, and its

serg [7]

Answer:

Let x be the width of the compartment,

Then according to the question,

The length of the compartment = x + 2

And the depth of the compartment = x -1

Thus, the volume of the compartment, $V = (x+2)x(x-1) = x^3 + x^2 - 2x$

But, the volume of the compartment must be 8 cubic meters.

⇒ $x^3 + x^2 - 2x = 8$

⇒ $x^3 + x^2 - 2x - 8=0$

⇒ $(x-2)(x^2+3x+4)=0$

If $x-2=0\implies x = 2$ and if $x^2+3x+4=0\implies x = \text{complex number}$

But, width can not be the complex number.

Therefore, width of the compartment = 2 meter.

Length of the compartment = 2 + 2 = 4 meter.

And, Depth of the compartment = 2 - 1 = 1 meter.

Since, the function that shows the volume of the compartment is,

$V(x) = x^3 + x^2 - 2x$

When we lot the graph of that function we found,

V(x) is maximum for infinite.

But width can not infinite,

Therefore, the maximum value of V(x) will be 8.

8 0

3 years ago

Read 2 more answers

11/12 of the disk space on a

svet-max [94.6K]

Answer:

2 whole number 1 out of 4

Step-by-step explanation:

11/12 x 3

11/4 = 2remainder 3

2 whole number 3 out of 12

When u reduce it will be 2 whole number 1 out of 4

8 0

3 years ago

The population is decreasing at a rate of 5% per year. If the population is 28,400 today, what will the population be in 8 years

Natali [406]

Answer:

710

Step-by-step explanation:

if its wrong tell me (☞ﾟヮﾟ)☞(if it right plz give me brainlist)☜(ﾟヮﾟ☜)

3 0

2 years ago

4×+12=36 what number goes in the x?

Nataliya [291]

You can work this out by rearranging the equation and isolating the x.

4x + 12 = 36

4x = 36 - 12 (I moved the +12 to the other side, which means it becomes -12)

4x = 24 (36 - 12 = 24)

x = 24 / 4 (You need to isolate the x, and because it was being multiplied by 4, I divided both sides by 4 to leave me with just x)

x = 6 (24 divided by 4 is 6).

8 0

3 years ago