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jolli1 [7]
3 years ago
9

Find the slope and y-intercept for the graph. God bless!

Mathematics
1 answer:
lions [1.4K]3 years ago
4 0
Slope: you can do rise/run by making a small triangle or you can use the slope formula.
Slope formula: pick any two points
(y2 - y1)/ (x2 - x1)
I found (1,1) and (2,4)
(4-1)/(2-1) = 3/1 = 3
The slope is 3

Y intercept = (0,y)
Find the point where x = 0
It would be (0,-2)
The y intercept is (0,-2)
You might be interested in
Iestion 10 (5 points)
marta [7]

Answer:

Jake is 9, and Jake's dad is 43.

Step-by-step explanation:

Ok, let's start off by putting a variable for Jack's age, A.

We know that Jack's father is 2 less than 5 times, so we can write his as 5x -2.

Now let's make an equation:

52 = x + 5x - 2

We need to isolate the x-values so we need to add 2 on both sides:

54= x + 5x

No we need to add the like terms:

54 = 6x

Finally, we just divide by 6 on each side.

Now we know X = 9 but we're not done yet :)

So because Jake's dad is almost 5 times as much, we first multiply Jack's age by 5. We get 45 but we need to subtract 2 which leaves us with 43.

3 0
3 years ago
The area of a square flowerbed is 1.21 square yards. What is the length of each side?
gregori [183]

Step-by-step explanation:

area of a square=a*a=a^2

1.21=a^2

a=√1.21

a=1.1yards

6 0
3 years ago
P^2 - 17p + 72 factor the trinomial. enter smaller number first ? answer (p+?)(p+?)
klio [65]

Answer:

(p - 8)(p - 9)

Step-by-step explanation:

We need  2 numbers whose product is + 72 and whose sum = -17.

They are -8 and -9


3 0
3 years ago
Write a real-world problem that can be modeled by the equation 1.25x=0.75x+50
dimulka [17.4K]
We have such equation
1.25x=0.75x+50        /-0.75x   (subtract 0.75 both sides)
1.25x-0.75x=0.75x-0.75x+50
0.5x=50          /*2   (multiply both sides times 2)
0.5x*2=50*2
x=100 - its the answer
7 0
3 years ago
What is the length of one leg of the triangle? 64 cm 64 StartRoot 2 EndRoot cm 128 cm 128 StartRoot 2 EndRoot cm.
zmey [24]

Answer:

Use the Pythagorean theorem for right triangles to solve this

a^2 + b^2 = c^2     where 'a' and 'b' are the legs of the triangle and 'c' is the hypotenuse

so:

8^2 + b^2 = 17^2     solve for the second leg, b

64 + b^2 = 289

b^2 = 289 - 64= 225

b = 15

7 0
3 years ago
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