So since you know that x^2-1 is equal to (x-1)(x+1),
you can figure that this factors to
(y^2-x^3)(y^2+x^3)
because you know how the difference of two squares formula, stated on the top line of this answer.
Answer:
107
Step-by-step explanation:
Answer:
0.59375
Step-by-step explanation:
3f(x) - f(1/x) = x^2
x = 2: 3f(2) - f(1/2) = 2^2
x = 1/2: 3f(1/2) - f(2) = (1/2)^2
Let a = f(1/2) and b = f(2):
3b - a = 4; 3a - b = 1/4
3b - 4 = a
3(3b-4) - b = 1/4
8b = 12 + 1/4
b = 1.53125
3 * 1.53125 - 4 = a
a = 0.59375
The geometrical relationships between the straight lines AB and CD is that they are parallel to each other
<h3>How to determine the relationship</h3>
It is important to note the following;
- A drawn from the origin and passes through point A (a , b), then the equation of OA = ax + by
- If a line is drawn from the origin and passes through point B (c , d), then the equation of OB = cx + dy
We find the equation of AB by subtracting OB from OA, thus AB = (c - a)x + (d - b)y
The slope of line AB =
⇒ OA= 2 x + 9 y
⇒ OA = 4 x + 8 y
⇒AB = OB - OA
⇒AB = (4 x + 8 y) - (2 x + 9 y)
⇒ AB = 4 x + 8 y - 2 x - 9 y
Collect like terms
⇒ AB = (4 x - 2 x) + (8 y - 9 y)
⇒AB = 2 x + -y
⇒ AB = 2 x - y
⇒ Coefficient of x = 2
⇒ Coefficient of y = -1
⇒ The slope of ab =
= 2
For CD
⇒ CD = 4 x - 2 y
⇒Coefficient of x = -4
⇒ Coefficient of y = -2
⇒The slope of cd =
= 2
Note that Parallel lines have same slopes
And Slope of ab = slope of cd
AB // CD
Therefore, the geometrical relationships between the straight lines AB and CD is that they are parallel to each other
Learn more about parallel lines here:
brainly.com/question/24607467
#SPJ1
Answer:
Step-by-step explanation:
–10.5 < 3a ⇒ -3.5 < a ⇒ a > -3.5
- <u>no</u> as variable has positive coefficient
b/6 ≤ 7 ⇒ b ≤ 42
- <u>no</u> as variable has positive coefficient
–4.5c > 9 ⇒ c < - 2
- <u>yes </u>as variable has negative coefficient
–21/5 ≤ –5/2d ⇒ (-21/5)*(-2/5) ≥ d ⇒ d ≤ 42/25
- <u>yes</u> as variable has negative coefficient