All categories

3 years ago

Pls help I really need it ASAP

Mathematics

2 answers:

gtnhenbr [62]3 years ago

8 0

Answer:

0, -1 for part A -1,-9 for part B

Step-by-step explanation:

gogolik [260]3 years ago

3 0

I would help but i’m not rlly a written response type of guy. hang in the tight the kid. someone will help soon

You might be interested in

Scientists released 8 rabbits into a new habitat in year 0

wariber [46]

Answer:

A. f(x)= 8(2)^x

Step-by-step explanation:

hope that helped

5 0

3 years ago

4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.

nikitadnepr [17]

Answer:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=1$

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0$

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}$

Step-by-step explanation:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))$

$=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})$

$=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1$

2nd

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}$

$=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0$

3th

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))$

$=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}$

What we use?

We use that

$e^{i\pi n}=cos(\pi n)+i sin(\pi n)$

and

$\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}$

6 0

4 years ago

The table represents a linear relationship.What is the sum of p and q

Rashid [163]

Can you show me the equation

5 0

3 years ago

-6=2n-n please help I hate math

Crank

Answer:

-6 = n

Step-by-step explanation:

-6=2n-n

Combine like terms

-6 = n

4 0

3 years ago

Read 2 more answers

Alon was curious if segments \overline{JK} JK start overline, J, K, end overline and \overline{NM} NM start overline, N, M, end

BartSMP [9]

The answer is A because Alon could have rotated the figure and discovered that they are congruent

6 0

4 years ago