Question

Find the zeros of the function. Enter the solutions from least to greatest.

Answer 1

Answer:

Lesser x is -13.

Greater x is 1.

Step-by-step explanation:

We have the function:

$f(x)=(x+6)^2-49$

And we want to find the zeros of the function.

So, set f(x) to 0 and solve for x:

$(x+6)^2-49=0$

Add 49 to both sides:

$(x+6)^2=49$

Take the square root of both sides. Since we're taking an even root, we will need plus/minus:

$x+6=\pm 7$

Subtract 6 from both sides:

$x=\pm7-6$

Evaluate for each case:

Case 1; 7 is positive:

$x=7-6=1$

Case 2; 7 is negative:

$x=-7-6=-13$

So, our zeros are:

$\{x|-13, 1\}$

Our lesser x is -13, and our greater x is 1.

And we're done!

Answer 2

Answer:

Our lesser x is -13, and our greater x is 1.

Step-by-step explanation: