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fredd [130]
3 years ago
9

Help...please it’s due in 35 minutes

Mathematics
1 answer:
loris [4]3 years ago
6 0

Answer:

a) 3/2 b) 5/1 c) Nathan

Step-by-step explanation:

it is Nathan because he runs 5 meters every second and Jay only runs 1.5 meters every second. hope this helps.

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Which expression has the least value when x=100?<br>A.1/x <br>b.10/x <br>c.1-x <br>D 10-x​
trapecia [35]

Answer:

C

Step-by-step explanation:

C will have the least value with -99.

A would be 1/100, which is 0.01, which is small, but larger than -99.

B would be 10/100, which is 0.1, which is larger than A.

C is 1-100, which equals -99.

D is 10-100, which equals -90. -99 is smaller than -90.

4 0
3 years ago
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Which graph best represents the equation 9x - 3y =15?<br> A. <br> B. <br> C. <br> D.
olganol [36]

Answer:

A

Step-by-step explanation:

I put the equation in Desmos graphing calculator

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3 years ago
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The quantity of a drug Q mg present in the body t hours after an injection of the drug is given is : Q = f (t) = 70 te-0.6tFind
solniwko [45]

Answer:

A) f(1) =38.43mg

B) f'(1) = -15.37 mg/hour

C) f(6) = 11.47mg

D) f'(6) = -4.97mg/hour

F) 23.06mg

H) 0

Step-by-step explanation:

Given the function:

Q = 70te^-0.6t........(1)

Where Q is measured in mg and t is in hours

(A) f(1) is the quantity Q in mg after 1 hour

f(1) = 70(1)e^-0.6(1) = 70e^-0.6

= 70×0.5488

= 38.43 mg

(B) f'(1) = dQ/dt, at t=1

= 70t × -0.6e^-0.6t +70e^-0.6t

= -42te^-0.6t + 70e^-0.6t

= -42(1) × 0.5488 + 70 × 0.5488

=28 × 0.5488

= -15.37mg/hour

(C) f(6) = 70te^-0.6t

= 70(6)e^-0.6(6)

= 420e^-3.6

= 420 × 0.0273

= 11.47mg

(D) f'(6) = dQ/dt, at t= 6

f' = -42te^-0.6t + 70e^-0.6t

f'(6) = -42(6)e^-3.6 + 70e^-3.6

= -252 × 0.0273 + 70 × 0.0273

= -6.8796 + 1.911

= -4.9686

= -4.97mg/hour

(E) f(1) is the quantity of the drug present in the body 1 hour after injection.

f'(1) is the rate of decrease of the drug 1 hour after injection or it is the rate at which the drug is decreasing 1 hour after injection.

(F) The quantity Q is given by

Q= 38.43 - 15.37

= 23.06mg

(G) f(6) is the quantity of the drug present in the body 6 hours after injection

f'(6) is the rate at which the drug is removed or decreased from the body 6 hours after injection.

(H) The quantity is given by

Q = 11.47 - 4.97×6

Q= 11.47-29.82

Q= -18.35mg

This is not possible, hence after 6 hours of injection the quantity of drug remaining is zero.

5 0
3 years ago
Multiply 986 and 19 together. Round to the nearest hundredth when necessary.
Ann [662]

Answer:

18734

Step-by-step explanation:

mark brainliest please:)

8 0
3 years ago
How do i do 5th grade math promblem solving
Nadya [2.5K]
U can just use google or ask for a teachers help
4 0
3 years ago
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