Answer:
def prompt_number():
while True:
number = int(input("Enter a number: "))
if number >= 0:
break
return number
def compute_sum(n1, n2, n3):
total = n1 + n2 + n3
return total
n1 = prompt_number()
n2 = prompt_number()
n3 = prompt_number()
result = compute_sum(n1, n2, n3)
print(result)
Explanation:
Create a function named prompt_number that asks the user to enter a number until a positive number or 0 is entered and returns the number
Create a function named compute_sum that takes three numbers, sums them and returns the sum
Ask the user to enter three numbers, call the prompt_number() three times and assign the values
Calculate the the sum, call the compute_sum and pass the numbers as parameters
Print the result
The best scenario is when a program suffers from frequent
page faults. In the situations when a kernel thread experiences a page fault,
another kernel thread can be switched in; something a single-threaded process
will not be capable of doing. Another best circumstance is when a program has
to wait for other systems events.
Answer:
Negative transfer of learning
Explanation:
Negative transfer of learning occur when the knowledge you've acquired in the past is/are interfering with the one(s) you are currently acquiring.
Example: learning a new language that have some differences in pronunciation from the previous one, changing from a right-sided vehicles to a left-sided vehicles etc.
#accepting input from user
n=int(input("Enter a number: "))
#entered number is stored in a temporary variable
temp=n
#initializng required variables
rev=0
dgt=0
#digits are reversed inside while loop
while(n>0):
dgt=n%10
rev=rev*10+dgt
n=n//10
#original number and its reverse are compared
if(temp==rev):
#if equal, it's a palindrome
print("It is a Palindrome")
else:
#if not equal, it's not a palindrome
print("It is not a Palindrome")
#◌⑅⃝●♡⋆♡Nåmřāthā♡⋆♡●⑅◌
Answer:
14.0
Explanation:
The loop converts each answer to a float. The accumulator variable adds the values entered.
2.0 + 5.0 + 1.0 + 6.0 = 14.0
