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3 years ago

2x^2+ 9x +4= Factor the expression

Mathematics

2 answers:

iragen [17]3 years ago

8 0

Answer:

(x+4)(2x+1)

Step-by-step explanation:

1. 2x^2+8x+x+4 ----- split the second term in 2x^2 + 9x+4 into two terms.

2. 2x(x+4)+(x+4) ----- Factor out common terms in the first two terms, then in the last two terms.

3.(x+4)(2x+1) ------ factor out the common term x+4

Westkost [7]3 years ago

3 0

(x+4) and (2x+1) :) there you go

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Vsevolod [243]

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4 years ago

Your school wants to take out an ad in the paper congratulating the basketball team on a successful season, as shown to the rig

iogann1982 [59]

Answer:

$x_1 =-14.43 in, x_2 = 2.426in$

Since the measurement can't be negative the correct answer for this case would be $x =2.426 in$

Step-by-step explanation:

Let's assume that the figure attached illustrate the situation.

For this case the we know that the original area given by:

$A_i = 7 in *5 in = 35in^2$

And we know that the initial area is a half of the entire area in red $A_i = \frac{A_f}{2}$ , so then:

$A_f = 2 A_ i =2*35 = 70$

And we know that the area for a rectangular pieces is the length multiplied by the width so we have this:

$70 = (x+7) (x+5)$

We multiply both terms using algebra and the distributive property and we got:

$70 =x^2 +12 x +5$

And we can rewrite the expression like this:

$x^2 +12 x -35 = 0$

And we can solve this using the quadratic formula given by:

$x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}$

Where $a = 1, b =12 and c=-35$ if we replace we got:

$x = \frac{-12 \pm \sqrt{(12)^2 -4(1)(-35)}}{2*1}$

And the two possible solutions are then:

$x_1 =-14.43 in, x_2 = 2.426in$

Since the measurement can't be negative the correct answer for this case would be $x =2.426 in$

3 0

3 years ago

PLS HELP ASAP calculate the distance between the two points. (18, -24) & (87, 100)

GarryVolchara [31]

Answer:

<h3>The answer is 141.90 units</h3>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(18, -24) & (87, 100)

The distance between them is

$d = \sqrt{ ({18 - 87})^{2} + ({ - 24 - 100})^{2} } \\ = \sqrt{ ( { - 69})^{2} + ( { - 124})^{2} } \\ = \sqrt{4761 + 15376} \\ = \sqrt{20137} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = 141.90489773...$