Which is the minimum value of the function y=x^2+8x+7

Mathematics

2 answers:

anygoal [31]2 years ago

8 0

The minimum value of the function is (-4, -9).

Aneli [31]2 years ago

7 0

You can do this by completing the square.
Y=x^2 + 8x + 7
= (x+4)^2 -16+7
= (x+4)^2 - 9

Minimum value = -9

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