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Svetach [21]
3 years ago
13

Which is the minimum value of the function y=x^2+8x+7

Mathematics
2 answers:
anygoal [31]3 years ago
8 0
The minimum value of the function is (-4, -9).
Aneli [31]3 years ago
7 0
You can do this by completing the square.
Y=x^2 + 8x + 7
= (x+4)^2 -16+7
= (x+4)^2 - 9

Minimum value = -9
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What is n in 3/5n + 15 =10+2/5n
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Simplify both sides of the equation.

<span><span><span><span>3/5</span>n </span>+ 15 </span>= <span><span><span>2/5</span>n </span>+ 10


</span></span>Subtract 2/5n from both sides.

<span><span><span><span><span>3/5</span>n </span>+ 15 - </span><span><span>2/5</span>n </span></span>= <span><span><span><span>2/5</span>n </span>+ 10 - </span><span><span>2/5</span>n</span></span></span><span><span><span><span>15</span>n </span>+ 15 </span>= 10


</span>Subtract 15 from both sides.

<span><span><span><span><span>1/5</span>n </span>+ 15 - </span>15 </span>= <span>10 - 15</span></span><span><span><span>1/5</span>n </span>= -<span>5


</span></span>Multiply both sides by 5.

<span><span>5 </span></span>× (1/5n) = (5) × (−5)<span>n = -<span><span>25


Answer: n is -25.</span></span></span>
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