The line crosses the y-axis at point (0,2). You know this because the slope intercept form is y=mx+b. y is any point on the y-axis. m is the slope of the line. x is and point on the x-axis. Finally, b is the y-intercept or where the line crosses the y-axis. As a result, your equation has a 2 for b. So, your answer would be: the line crosses the y-axis at point (0,2). 2 being where the line crosses the y-axis.
Answer:
See below
Step-by-step explanation:
13) Domain: x -> {-3,-2,-1,0,1,2}, Range: f(x) -> {5}
14) Notice how x can't be -4 as that will make the denominator 0. Therefore, your domain is (-∞,-4)U(-4,∞) and your range is [0,∞) since 0 is the lowest possible real y-value that satisfies the equation (recall that if y<0, you are unable to find the real square root of a real number)
AB (y=3) and CD (y=6) are parallel, but different lengths. The figure is a trapezoid. A diagram shows it to be an isosceles trapezoid.
Answer:
1st answer
Step-by-step explanation:
