Question

Find the difference of functions s and r shown below. r(x) = -x² + 3x s(x) = 2x + 1 ( s-r)(x)=​

Answer 1

Answer:

Part 1)

$(s-r)(x)=(2x+1)-(-x^2+3x)$

Part 2)

$(s-r)(x)=x^2-x+1$

Step-by-step explanation:

Part 1)

So we have the two functions:

$r(x)=-x^2+3x\text{ and } s(x)=2x+1$

And we want to find:

$(s-r)(x)$

This is the same as:

$=s(x)-r(x)$

Substitute:

$=(2x+1)-(-x^2+3x)$

So, our answer for Part A is:

$=(2x+1)-(-x^2+3x)$

Part 2)

Let's find our difference.

Distribute the -1:

$=(2x+1)+(x^2-3x)$

Combine like terms:

$=(x^2)+(2x-3x)+(1)$

Add:

$=x^2-x+1$

And we're done!

Answer 2

Answer:

1st box is (2x+1)-(-x^2+3x)    2nd box is x^2 - x + 1

Step-by-step explanation:

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