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Novosadov [1.4K]

3 years ago

5

Help i will give 20 points!!

2 answers:

Allisa [31]3 years ago

5 0

I filled out the answers for you

posledela3 years ago

3 0

Y is the very top, X is the other one, origin is labeled (0,0) A is the very first box going from left to right B is the highest box and C is the lowest

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Which type of sequence is shown? Check all that apply. 4, 8, 12, 16, . . . The numbers are quickly getting larger, so this is a

melisa1 [442]

Step-by-step explanation:

4, 8 , 12 , 16 .....

This is an arithmetic sequence because there is a common difference of 4 between each term.
This is a geometric sequence because there is a common ratio of 2 between each term.

Hope it will help.

7 0

3 years ago

Evaluate the given expression. Subscript 5 Baseline P Subscript 2 a. 40 c. 25 b. 32 d. 20

Leto [7]

Answer:

d. 20

Step-by-step explanation:

The given question implies 5 permutation 2, i.e $_{5}$ $P_{2}$ .

But,

$_{n}$ $P_{r}$ = $\frac{n!}{(n - r)!}$

So that for $_{5}$ $P_{2}$ , n = 5 and r = 2.

$_{5}$ $P_{2}$ = $\frac{5!}{(5 - 2)!}$

= $\frac{5!}{3!}$

= $\frac{5*4*3*2!}{3*2!}$

Cancel out 3 and 2 with respect to the numerator and denominator.

$_{5}$ $P_{2}$ = 5 * 4

= 20

Therefore,

$_{5}$ $P_{2}$ = 20

So that the correct option is D.

6 0

3 years ago

Read 2 more answers

48 is what percent of 75

Dahasolnce [82]

Answer:

36

Step-by-step explanation:

Hope this helps!

8 0

3 years ago

What are the roots of f(x) = x2 – 48? –48 and 48 –24 and 24 Negative 8 StartRoot 3 EndRoot and 8 StartRoot 3 EndRoot Negative 4

Ivanshal [37]

Answer:

$x=4\sqrt{3},\:x=-4\sqrt{3}$ are the roots.

Step-by-step explanation:

$x=4\sqrt{3},\:x=-4\sqrt{3}$

Considering the expression

$x^2\:-\:48$

Solving

$x^2-48=0$

$x^2-48+48=0+48$

$x^2=48$

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=\sqrt{48},\:x=-\sqrt{48}$

Solving

$x=\sqrt{48}$

= $\sqrt{2^4\cdot \:3}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}$

= $\sqrt{3}\sqrt{2^4}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^m}=a^{\frac{m}{n}}$

$\sqrt{2^4}=2^{\frac{4}{2}}=2^2$

$=2^2\sqrt{3}$

$=4\sqrt{3}$

So,

$x=4\sqrt{3}$

Similarly,

$x=-\sqrt{48}=-4\sqrt{3}$

Therefore, $x=4\sqrt{3},\:x=-4\sqrt{3}$ are the roots.

Keywords: roots, expression

Learn more about roots from brainly.com/question/3731376

#learnwithBrainly

9 0

3 years ago

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Surfave area of cylinder Round to the nearest tenth

Ainat [17]

Im pretty dure the area is 62.83

4 0

3 years ago