14r+20<14r+16 or 8−10r>15−9r
14r+20<14r+16
14r+20−14r<14r+16−14r(Subtract 14r from both sides)
20<16
20−20<16−20(Subtract 20 from both sides)
0<−4
8−10r>15−9r
−10r+8>−9r+15(Simplify both sides of the inequality)
−10r+8+9r>−9r+15+9r(Add 9r to both sides)
−r+8>15
−r+8−8>15−8(Subtract 8 from both sides)
−r>7
−r/−1 > 7/−1(Divide both sides by -1)
r<−7
Ur answer is:
r < - 7 OR 0 < - 4
Answer:
6x6
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Please give me brainliest :)
Answer:
B. is greater than
Step-by-step explanation:
As the graph of function f(x) is a parabola, so that the equation of function f(x) is: f(x) = 
As it can be seen in thee figure, the graph of function f(x) cross points (0;8) ;(-2; 0) and (4;0)
=> f(0) = 8; f(-2) = 0; f(4) = 0
We have:
- f(x=0) = a x 0 + b x 0 + c = 8 => c = 8
- f (x=-2) =
= 4a -2b + 8 = 0
- f (x=4) =
= 16a + 4b + 8 = 0
We have:
+) 4a -2b + 8 = 0 => 2 x (4a -2b + 8) = 8a - 4b + 16 = 0 (1)
+) 16a + 4b + 8 = 0 (2)
We take (2) minus (1)
=> (16a + 4b + 8) - (8a - 4b + 16) = 0
=> 8a - 8 = 0 => a = 1
Replace a = 1 into (1)
=> 8 x 1 - 4b + 16 = 0 => b = 6
So that: 
f (2) = 2^2 + 6 x 2 + 8 = 24
g (2) = 3 -2 + 2 = 3
<em>=> f(2) is greater than g(2)</em>