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vichka [17]
3 years ago
7

Find an angle between 0 and 2pi that is coterminal with the following angle. 32pi/9

Mathematics
1 answer:
never [62]3 years ago
5 0
<span>To do these you will be adding or subtracting  2pi (or integer multiples of .

Since the given angles are in fraction form, it will help to have 2pi  in fraction form, 2pi=10/5=6pi/3=4pi/2=18pi/9     NOTE: this>(/) stands for over like 1 over 2 EX. 1/2

too, so the addition/subtraction is easier.

Hint: When deciding if you have a number between 0 and 2pi, compare it to the fraction version of 2pi that you've been adding/subtracting.


For 17pi/5...
First we can see that 17pi/5 is more than 10pi/5 (aka 2pi). So we need to start subtracting: 17pi/5 - 10pi/5 = 7pi/5

Now we have a number between 0 and 10pi/5. So 7pi/5 is the co-terminal angle between 0 and 2pi.

I'll leave the others for you to do. Just remember that you might have to add or subtract  multiple times before you get a number between 0 and 2pi.
P.S don't add or subtract at all if the number starts out between 0 and 2pi.</span>
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3 0
3 years ago
Assume that y varies directly with x then solve y = 2.5 x = .5 when x = 20
velikii [3]

Step-by-step explanation:

y=2.5| ?

x=0.5| 20

It'll be criss-crossed then it'll be:-

2.5×20=50

5 0
3 years ago
If f(x) = 2x2 and g(x)= x2 + 2x, which expression represents f(g(x))?
andre [41]

Answer:

f(g(x)) = 2(x^2 + 2x)^2

f(g(x)) = 2x^4 + 8x^3 + 8x^2

Step-by-step explanation:

Given;

f(x) = 2x^2

g(x) = x^2 + 2x

To derive the expression for f(g(x)), we will substitute x in f(x) with g(x).

f(g(x)) = 2(g(x))^2

f(g(x)) = 2(x^2 + 2x)^2

Expanding the equation;

f(g(x)) = 2(x^2 + 2x)(x^2 + 2x)

f(g(x)) = 2(x^4 + 2x^3 + 2x^3 + 4x^2)

f(g(x)) = 2(x^4 + 4x^3 + 4x^2)

f(g(x)) = 2x^4 + 8x^3 + 8x^2

Hope this helps...

7 0
3 years ago
Consider the function f(x)=−5x−8 and find the following: a) The average rate of change between the points (−1,f(−1)) and (3,f(3)
kipiarov [429]

Answer:

a. -5

b.-5

c.-5

Step-by-step explanation:

In order to find the average rate of change of a function , we divide the change in the output value by the change in the input value.

Generally, the average rate of change (ARC) on an ecuatios  between two points (x1,f(x1)) and (x2,f(x2)) is

  • ARC = [f(x2)-f(x1)]/ (x2-x1)

<em>In case a)</em>

f(-1)= -5*(-1)-8=5-8= -3          f(3)= -5*3-8= -23

Then ARC= (-23-(-3))/(3-(-1))=-20/4=-5

<em>In case b)</em>

f(a)= (-5a-8)

f(b)= (-5b-8)

Then ARC= [(-5b-8)-(-5a-8)]/(b-a)= (-5b+5a)/(b-a)= -5(b-a)/(b-a)= -5

<em>In case c)</em>

f(x)= -5x-8

f(x+h)= -5(x+h)-8= -5x-5h-8

then ARC= [(-5x-5h-8)-(-5x-8)]/(x+h-x) =-5h/h= -5

3 0
3 years ago
PLEASE ANSWER I WILL MARK BRAINLIEST AND AWARD A LOT OF POINTS!!!!!Jeremiah is creating a playlist that has only one song from e
lord [1]

Answer:

448

Step-by-step explanation:

4*2*7*8=448 different combinations

6 0
3 years ago
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