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kari74 [83]
3 years ago
13

Is the gcf of a pair of numbers ever equal to one of the numbers

Mathematics
1 answer:
Marianna [84]3 years ago
3 0
No it's a number that can be found in both of the factor lists.
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PLEASE HELP ASAP!!!! WORTH 15 POINTS!
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Answer:

Its C I know but I have my friend that knows this by heart

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3 years ago
What is the interest earned on $20,000 for five years, at an interest rate of 3% compounded daily?
SSSSS [86.1K]

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The final balance is $23,232.33.

The total compound interest is $3,232.33.

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3 years ago
Suppose a football is kicked with an initial velocity of 82 ft/sec., at an angle of
satela [25.4K]

Answer:

The position P is:

P = 87\^x + 75\^y ft     <u><em> Remember that the position is a vector. Observe the attached image</em></u>

Step-by-step explanation:

The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity s_0 is:

y(t) = y_0 + s_0t -16t ^ 2

Where y_0 is the initial height = 0 for this case

We know that the initial velocity is:

82 ft/sec at an angle of 58 ° with respect to the ground.

So:

s_0 = 82sin(58\°) ft/sec

s_0 = 69.54 ft/sec

Thus

y(t) = 69.54t -16t ^ 2

The height after 2 sec is:

y(2) = 69.54 (2) -16 (2) ^ 2

y(2) = 75\ ft

Then the equation that describes the horizontal position of the ball is

X(t) = X_0 + s_0t

Where

X_ 0 = 0 for this case

s_0 = 82cos(58\°) ft / sec

s_0 = 43.45 ft/sec

So

X(t) = 43.45t

After 2 seconds the horizontal distance reached by the ball is:

X (2) = 43.45(2)\\\\X (2) = 87\ ft

Finally the vector position P is:

P = 87\^x + 75\^y ft

6 0
3 years ago
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rjkz [21]

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The midpoint is ( 7,5)

Step-by-step explanation:

To find the x coordinate of the midpoint, add the x coordinate of the endpoints and divide by 2

( 4+10)/2 = 14/2 = 7

To find the y coordinate of the midpoint, add the y coordinate of the endpoints and divide by 2

(8+2)/2 = 10/2 = 5

The midpoint is ( 7,5)

6 0
3 years ago
If pr=5 in and pt=8in what is rs
Nadya [2.5K]
5(5+8)= RS^2
25+40=IRSI^{2}
65= IRSI^{2}
IRSI^{2} =\sqrt{65}

Hope it helps!
#MissionExam001
7 0
3 years ago
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