Let the width be x.
Length = 2x -1
The area of rectangle = 45 cm²
x*(2x -1) = 45
2x² -x = 45
2x² -x - 45 = 0 This is a quadratic equation
comparing to ax² + bx + c = 0, a = 2, b = -1, c = -45
x = (-b + √(b² -4ac)) / 2a or (-b - √(b² -4ac)) / 2a
x = (- -1 + √((-1)² -4*2*-45)) / 2*2 or (- -1 - √((-1)² -4*2*-45)) / 2*2
x = (1 + √(1 +360)) / 2*2 or (1 - √(1 + 360) / 2*2
x = (1 + √361) / 4 or (1 - √361) / 4
x = (1 + 19) / 4 or (1 - 19) / 4
x = 20/4 or -18/4
x = 5 or -4.5
x can't be negative since we are solving for side.
x = 5 as the only valid solution.
Recall, the width = x = 5.
Length = 2x - 1 = 2*5 - 1 = 10 - 1 = 9
Hence the length = 9cm , and width = 5cm
Answer:
33.8 sq cm
Step-by-step explanation:
Required Area = Area of rectangle - Area of semicircle
THEOREM:
<u>Pythagorean theorem</u>:— In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides.
ANSWER:
By pythagorean property,
x² = 6² - 3²
x² = 36 - 9
x² = 27
x = √27 units.
So, <u>Correct choice</u> - [A] √27 units.
