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Fynjy0 [20]
3 years ago
15

Find the value of x in the triangle shown below. a. x=27 b. x=5 c. x= 4 d. x=18

Mathematics
2 answers:
Ivahew [28]3 years ago
5 0

THEOREM:

<u>Pythagorean theorem</u>:— In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides.

ANSWER:

By pythagorean property,

x² = 6² - 3²

x² = 36 - 9

x² = 27

x = √27 units.

So, <u>Correct choice</u> - [A] √27 units.

Misha Larkins [42]3 years ago
5 0

Answer:

\huge\mathfrak\pink{S} \huge\mathfrak\purple{o} \huge\mathfrak\blue{l} \huge\mathfrak\red{u} \huge\mathfrak\green{t} \huge\mathfrak\pink{i}\huge\mathfrak\purple{o}\huge\mathfrak\red{n}\huge\mathfrak\orange{➔}\

by using Pythagoras law:

h²=p²+b²

6²=x²+3²

x²=36-9

x=√27 units

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Use the remainder theorem to find P (3) for P(x) = 2x² - 4x^2- 3.
ladessa [460]

Answer:

P(2) = 4

Step-by-step explanation:

P(X) = -2X4 + 4X3 - X + 6

Use the remainder theorem to find quotient and remainder and the value of P(2)

 

First add in any missing exponents:  P(x) = -2x4 + 4x3 + 0x2 -x + 6

 

Write all the coefficients in a line (including the constant) with the number being solved for off to the left:

 

Bring down the first coefficient (-2), multiply it by the term in question (2), carry the product up under

the 2nd coefficient and then add down (4-4=0), carry up the sum and repeat process across.  The last

sum is the answer for P(2)

 

 

(2)   -2    4    0    -1    6

            -4    0      0  -2

      __________________

       -2   0    0     -1   4

 

P(2) = 4

 

check the answer:  P(2) = -2(24) + 4(23) -2 + 6 = -2(16) +4(8) + 4 = 4    Our answer is correct

 

The quotient is what we would bet by dividing the original equation by the polynomial (x-2). The

answer is given by the bottom numbers which will begin an one lower exponent than the original.

Quotient is:   -2x3 + 0x2 + 0x -1 = 2x3 - 1

The remainder is:   4/(x-2)

6 0
4 years ago
Evaluate M^2 /p^2 for M = 10, N =-5p and P = -2
kondaur [170]

<u>Answer: </u>

The solution of \bold{\frac{M^{2}}{P^{2}}} for M = 10, N = -5P and P = -2  is 25

<u>Solution: </u>

From question, given that the value of M is 10 and N is -5p and P is -2

We have to evaluate the value of \frac{M^{2}}{P^{2}},  

By substituting the values of M and N, we get

\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}

Expanding \bold{10^{2}}:

Here 10 is the base value and 2 is the exponent value. So the base term 10 is multiplied by itself two times.

10^{2} = 10 \times 10 = 100

Similarly expanding \bold{(-2)^{2}}:

Here -2 is the base term and 2 is the exponent value. So the base term -2 is multiplied by itself two times.  

(-2)^{2} = -2 \times -2 = 4

So the equation \frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}} becomes,

\frac{M^{2}}{P^{2}} = \frac{100}{4}

By dividing 100 by 4 , we get the result as 25

Hence the solution of \bold{\frac{M^{2}}{P^{2}}} when M = 10 and P = -2 is 25

6 0
4 years ago
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