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eimsori [14]
3 years ago
11

2.5x + 8.5y=90 what is the number for x

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
8 0

Answer:

It will have infinitely many solutions depending upon value of y.

For eg:

<u>Put y=10,</u>

2.5x+8.5×10=90

2.5x=5

x=2

<u>For y=0 </u>

x=90/2.5=36

and so on

You need a system of linear equations to get a single solution for x

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6 cases ordered
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Split 7 ways, each restaurant gets (1/7) of the total order = 6p/7 jars.

I sure hope 'p' is a multiple of 7, or else Harrison might
need to deal with the number of pickles in each jar.
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At Paul's bowling alley,it costs 4.00 to rents shoes and 3.50 to bowl each game. At Maggie's bowling alley, it costs 3 to rent s
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Answer: it will take 4 games for both costs to be the same.

Step-by-step explanation:

Let x represent the number of games that must be bowled before the costs become the same.

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3.5x + 4

At Maggie's bowling alley, it costs 3 to rent shoes and 3.75 to bowl each game. This means that the cost of bowling x games at Maggie's bowling alley would be

3.75x + 3

Therefore, for the costs to be the same, the number of games would be

3.5x + 4 = 3.75x + 3

3.75x - 3.5x = 4 - 3

0.25x = 1

x = 1/0.25 = 4

4 0
3 years ago
In a re survey 3 out of 8 people preferred the vanilla yogurt over the strawberry yogurt if there were a total of 120 surceyed h
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Henry is three more than twice Nicholas’ age. Marcus is 9 less than six times Nicholas’s age. If Henry and Marcus are twins, how
blagie [28]

Answer:

Step-by-step explanation:

Henry is 3 more than twice Nicholas' age. You can write this as :

H = 3 + 2N

Marcus is 9 less than 6 times Nicholas' age:

M = 6N - 9

Since Henry and Marcus are twins, this means H = N.

3 + 2N = 6N - 9

Add 9 to both sides

12 + 2N = 6N

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12 = 4N

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8 0
3 years ago
A certain brand of refrigerator has a useful life that is normally distributed with mean 10 years and standard deviation 3 years
juin [17]

Answer: 0.55567

Step-by-step explanation:

Given : A certain brand of refrigerator has a useful life that is normally distributed with mean 10 years and standard deviation 3 years. The useful lives of these refrigerators are independent.

i.e.

\mu=10\text{ years}\\\sigma=3\text{ years}

Let X_1 and X_2 are two randomly selected refrigerator's life whose sum will exceed third selected refrigerator X_3 .

So that, X =X_1+X_2-1.9\times X_3

Mean =E(X_1)+E(X_2)-E(X_3)=10+10-1.9\times10 =1

Standard deviation =\sqrt{(Var(X_1)+Var(X_1)+Var(X_1))}

=\sqrt{(3^2+3^2+(1.9\times3)^2)}

=7.1056315694

Z-score : z=\dfrac{X-E[x]}{\sqrt{Var[x]}}=\dfrac{0-1}{7.0156315694}\approx-0.14

Now , The  probability that the total useful life of two(i..e n=2) randomly selected refrigerators will exceed 1.9 times the useful life of a third randomly selected refrigerator would be :-

P(Z>-0.14)=P(Z

Hence, the required probability is 0.55567.

3 0
3 years ago
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