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Mathematics

1 answer:

nignag [31]2 years ago

8 0

Answer:

Honestly, same. I have 3 warnings for forking arround and got some of my brainliest taken away. But what in the world did you do??

Step-by-step explanation:

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A used car was purchased in July 1999 for $11,900. If the car depreciates 13% of it's value each year, what is the value of the

trapecia [35]

1999 price = 11900
it depreciates 13%
$\frac{13}{100} \times 11900 = 1547$
year 2000 cost = 11900 - 1547 = 10353
it depreciates 13%
$\frac{13}{100} \times 10353 = 1345.89$
year 2001 cost = 10353 - 1345.89 = 9007.11
it depreciates 13%
$\frac{13}{100} \times 9007.11 = 1170.92$
year 2002 cost = 9007.11 - 1170.92 = 7836.19
pls mark as brainliest

8 0

3 years ago

Sketxh the graph of y=(x+3)^3 and state the points where the graph crosses the axes

gtnhenbr [62]

Answer: the graph crosses the x-axis at x = -3

<u>Step-by-step explanation:</u>

y = (x + 3)³

To find where the graph crosses the x-axis, let y = 0 and solve for x:

0 = (x + 3)³

0 = (x + 3) with a multiplicity of 3

-3 = x with a multiplicity of 3.

Since multiplicity is an ODD number, the graph CROSSES the x-axis at x = -3

<em />

<u>Graph:</u>

Leading coefficient is POSITIVE so right side goes to +∞
Degree of polynomial is ODD so left side goes to -∞

<em>graph is attached</em>

6 0

3 years ago

What is 8mn⁵-2m⁶+5m²n⁴-m³n³+n⁶-4m⁶+9m²n⁴-mn⁵-4m³n³ in standar form?

vovangra [49]

The expression in standard form is n⁶ + 7mn⁵ + 14m²n⁴ - 5m³n³ - 6m⁶

<h3>How to express in standard form?</h3>

The expression is given as:

8mn⁵-2m⁶+5m²n⁴-m³n³+n⁶-4m⁶+9m²n⁴-mn⁵-4m³n³

Collect the like terms

8mn⁵ -mn⁵ - 2m⁶ -4m⁶ + 5m²n⁴ +9m²n⁴+n⁶ - 4m³n³ - m³n³

Evaluate the like terms

7mn⁵ - 6m⁶ + 14m²n⁴+n⁶ - 5m³n³

Rewrite in standard form

n⁶ + 7mn⁵ + 14m²n⁴ - 5m³n³ - 6m⁶

Hence, the expression in standard form is n⁶ + 7mn⁵ + 14m²n⁴ - 5m³n³ - 6m⁶