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AlekseyPX
3 years ago
10

Offering 20 points to whoever answers all of themmmmmmm!

Mathematics
2 answers:
s2008m [1.1K]3 years ago
7 0

Answer:

The first is 30

Step-by-step explanation:

The third is 115

Otrada [13]3 years ago
4 0

Answer:

N1. x=180-30=150

N2. x=180-30=150 y=180-130-15=35

N3. x=180-65=115

N4. 3x+1=85 3x=84 x=26

Step-by-step explanation:

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Enter the value for x that makes the equation 1/2 (4x+12)+5x=30 true.
8090 [49]
First, distribute the (1/2) into (4x+12) by multiplying them.

The equation becomes:

2x + 6 + 5x = 30

On the left side, combine “like terms” through addition.

7x + 6 = 30

Subtract 6 from both sides:

7x = 24

Finally, get x alone by dividing both sides by 7:

x = 24/7, or if you wanted to round the decimal answer, it’s about 3.429.
8 0
3 years ago
PLZ sub to JD Outdoors & Gaming on yt I would really appreciate it.
timofeeve [1]

Answer:

Is that on YT

Step-by-step explanation:

7 0
2 years ago
given the functions f(x)=4x^2-1, g(x)=x^2-8x+5, and h(x)=-3x^2-12x +1, rank them from least to greatest based on their axis of s
Lesechka [4]
The formula for axis of symmetry is -b/2a.

For f(x):
0/2(4)
0/8
Axis of symmetry= 0

For g(x)
-(-8)/2(1)
8/2
Axis of symmetry= 4

For h(x)
-(-12)/2(-3)
12/-6
Axis of symmetry= -2

Order from least to greatest: -2, 0, 4

Final answer: h(x), f(x), g(x)
7 0
2 years ago
Which shows one way to determine the factors of x3 + 5x2 – 6x – 30 by grouping?
frutty [35]

Answer:

D

Step-by-step explanation:

group them first :

( x3+5x2) and ( -6x-30)

then simply by gcf ( greatest common factor) :

x2(x+5) and -6(x+5)

and just add them together:

x2(x+5)-6(x+5)

bonus :

it can be written as (x2-6)(x+5)

6 0
3 years ago
Find x<br><br><br><br><br> Thanks for the help in advance!
Marina86 [1]

I'm not sure if this is the easiest way of doing this, but it surely work.

Let the base of the triangle be AB, and let CH be the height. Just for reference, we have

AH=2,\quad HB=6,\quad AC=x

Moreover, let CH=y and BC=z

Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system

\begin{cases}4+y^2=x^2\\36+y^2=z^2\\x^2+z^2=64\end{cases}

If we solve the first two equations for y squared, we have

y^2=x^2-4\\y^2=z^2-36

And we can deduce

z^2 = x^2+32

So that the third equation becomes

x^2+x^2+32=64 \iff 2x^2 = 32 \iff x^2=16 \iff x=4

(we can't accept the negative root because negative lengths make no sense)

7 0
2 years ago
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