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balandron [24]
3 years ago
10

Answer the attachment.​

Mathematics
1 answer:
Rudik [331]3 years ago
3 0
C.) 15,600

Since you are using letters as your password and you can't use each letter more than once, you have to do 26×25×24.

26 first because there are 26 letters in the alphabet, then 25 because you already used one letter and can't use it again, then 24 because you used two letters that can't be reused. Multiply those together and you should get 15,600.

Hope this helps!
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2.5 quarters weigh approximately 1 ounce. How many pounds would you expect a
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Answer:

1.5 pounds

Step-by-step explanation:

$15=60 quarters

2.5x16 = 40 quarters per pound

60/40 = 1.5 pounds

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3 years ago
A consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 5​% will need repairs​
gtnhenbr [62]

Answer:

a) 0.5476

b) 0.0676

c) 0.4524

Step-by-step explanation:

Given this information, we can conclude that 74% of the cars won't need any repairs over a 1-year period (100 - 20 - 5 - 1 = 74%). And 26% will need at least 1 repair over a 1-year period.

P(car doesn't need repair) = 0.74

P (car needs repair) = 0.26

If you own two cars, the probability that:

<u>a) Neither will need repair:</u>

We need that car 1 won't need repair AND car 2 won't need repair.

=P(Car 1 doesn't need repair) x P(Car 2 doesn't need repair)

= 0.74 x 0.74 = 0.5476

The probability that neither will need repair is 0.5476.

<u>b) Both will need repair:</u>

We need that car 1 needs repair AND car 2 needs repair.

P(Car 1 needs repair) x P(Car 2 needs repair)

= 0.26 x 0.26 = 0.0676

The probability that both will need repair is 0.0676

<u>c) At least one car will need repair</u>

Car 1 needs repair or Car 2 needs repair or both need repair.

To solve this one, it's easier to use the complement of P(neither needs repair)

1 - P(neither needs repair)

1 - (0.74)(0.74)  = 1 - 0.5476 = 0.4524

The probability that at least one car will need repair is 0.4524

4 0
3 years ago
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