A student correctly write 0.15 as a percent. Of the student writes the answer in the form x % , what is the value of x

Mathematics

1 answer:

Fynjy0 [20]3 years ago

8 0

Answer:

The answer should be 15%

Step-by-step explanation:

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3 years ago

Please help. How do you find cosine, sine, cosecant and secant with this triangle?

Veseljchak [2.6K]

Hi there! You have to remember these 6 basic Trigonometric Ratios which are:

sine (sin) = opposite/hypotenuse
cosine (cos) = adjacent/hypotenuse
tangent (tan) = opposite/adjacent
cosecant (cosec/csc) = hypotenuse/opposite
secant (sec) = hypotenuse/adjacent
cotangent (cot) = adjacent/opposite
cosecant is the reciprocal of sine
secant is the reciprocal of cosine
cotangent is the reciprocal of tangent

Back to the question. Assuming that the question asks you to find the cosine, sine, cosecant and secant of angle theta.

What we have now are:

Trigonometric Ratio
Adjacent = 12
Opposite = 10

Looks like we are missing the hypotenuse. Do you remember the Pythagorean Theorem? Recall it!

a²+b² = c²

Define that c-term is the hypotenuse. a-term and b-term can be defined as adjacent or opposite

Since we know the value of adjacent and opposite, we can use the formula to find the hypotenuse.

10²+12² = c²
100+144 = c²
244 = c²

Thus, the hypotenuse is:

$\large \boxed{c = 2 \sqrt{61} }$

Now that we know all lengths of the triangle, we can find the ratio. Recall Trigonometric Ratio above! Therefore, the answers are:

cosine (cosθ) = adjacent/hypotenuse = 12/(2√61) = 6/√61 = (6√61) / 61
sine (sinθ) = opposite/hypotenuse = 10/(2√61) = 5/√61 = (5√61) / 61
cosecant (cscθ) is reciprocal of sine (sinθ). Hence, cscθ = (2√61/10) = √61/5
secant (secθ) is reciprocal of cosine (cosθ). Hence, secθ = (2√61)/12 = √61/6