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4 years ago

Question three (1 point)

Mathematics

1 answer:

laila [671]4 years ago

7 0

Answer:

B. $(-2,-3)$

Step-by-step explanation:

we know that

If a ordered pair is a solution of a linear equation. then the ordered pair must satisfy the linear equation

In this problem we have

$7x-5y=1$

<u>verify each case</u>

case A) $(-3,-2)$

substitute the value of x and the value of y in the linear equation and then compare

$7(-3)-5(-2)=1$

$-11=1$ -----> is not true

therefore

The ordered pair case A) is not a solution

case B) $(-2,-3)$

substitute the value of x and the value of y in the linear equation and then compare

$7(-2)-5(-3)=1$

$1=1$ -----> is true

therefore

The ordered pair case B) is a solution

case C) $(0,4)$

substitute the value of x and the value of y in the linear equation and then compare

$7(0)-5(4)=1$

$-20=1$ -----> is not true

therefore

The ordered pair case C) is not a solution

case D) $(4,0)$

substitute the value of x and the value of y in the linear equation and then compare

$7(4)-5(0)=1$

$28=1$ -----> is not true

therefore

The ordered pair case D) is not a solution

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

We need to factor the term $(5x^5) - (80x^3)$

First we can see that $5x^3$ is common in both terms

So, taking $5x^3$ common:

$(5x^5) - (80x^3)\\=5x^3(x^2-16)$

We can write $x^2-16$ as $(x)^2-(4)^2$

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Now we can solve $(x)^2-(4)^2$ using the formula: $a^2-b^2=(a+b)(a-b)$

We can write:

$=5x^3((x)^2-(4)^2)\\=5x^3(x-4)(x+4)$

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Given:
n = 150, sample size
Denote the sample proportion by q (normally written as $\hat{p}$ ).
That is,
q = 60/150 = 0.4, sample proportion.

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