The slope of the red line that is perpendicular to the green line is: -5/2.
<h3>What are the Slope Values of Perpendicular Lines?</h3>
When one line lies perpendicular to another line, the slope of one must be the negative reciprocal of the other line.
<h3>What is the Negative Reciprocal of a Number?</h3>
If given a number, i.e. a/b, the negative reciprocal of a/b would the opposite value of the reciprocal of a/b.
Reciprocal of a/b is b/a. Negative reciprocal of a/b would therefore be: -b/a.
Given that the slope of the green line is: 2/5. And it is perpendicular to the red line. The slope of the red line would be the negative reciprocal of 2/5.
Negative reciprocal of 2/5 is -5/2.
Therefore, the slope of the red line is: -5/2.
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1) domain: x cannot be -1/3, 0
2) domain: m cannot be 4/3, -7/2
3) domain: m cannot be 3
Answer:
2x+5y=-15
ax+bx=c
slope=-a/b so -2/5 matches up with point slope form
then to get y intercept substitite x in point slope for 0 and solve for Y to get -3
then do c/b to get y intercept, so -15/5, which equals -3.
Remove parentheses
3m - 7m+12 = 2 m-3
collect like terms
3m-7m-12 = 2m-6
move terms
-4m - 12 = 2m-6
collect the like terms and calculate
-4m-2m = -6+12
divide both sides by -6
-6m=6
m= -1
Remark
There's a lot you don't know here. Are DE and GF parallel? Is B a right angle? You can't assume that it is. The safest way to proceed is to give x in terms of 58 and B. You might get an answer that gives you something like 32 but I don't think you can say that unless you are told somewhere that ABC is a right angle triangle with the right angle at B.
So what to do.
<BAC = 58o That's because <BAC = <IAK They vertically opposite.
<ABC + <BAC + <ACB = 180o All triangles have 180o
<ACB = 180 - 58 - <ABC Solve for an unknown angle of a triangle.
<ACB = 122 - <ABC
x = <ACB Vertically opposite angles.
x = 122 - <ABC Answer It's 32 if ABC is a right angle.
