Answer:
a) P(X∩Y) = 0.2
b) 
= 0.16
c) P = 0.47
Step-by-step explanation:
Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.
So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67
Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:
P(X∩Y) = P(X) + P(Y) - P(X∪Y)
P(X∩Y) = 0.36 + 0.51 - 0.67
P(X∩Y) = 0.2
On the other hand, the probability that he must stop at the first signal but not at the second one can be calculated as:
= P(X) - P(X∩Y)
= 0.36 - 0.2 = 0.16
At the same way, the probability 
that he must stop at the second signal but not at the first one can be calculated as:
= P(Y) - P(X∩Y)
= 0.51 - 0.2 = 0.31
So, the probability that he must stop at exactly one signal is:
Answer:
Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form:
x≤−3
Interval Notation: ( − ∞ , − 3 ]
You can multiply 16<span> by 3 (the only prime factor of </span>24<span> not shared by </span>16), to find the LCM<span>: 3 * </span>16<span> = 48</span>
-- So 48 is the answer
Answer:
60 minutes
Step-by-step explanation:
to find this, we will first determine how long it takes austin to run one mile.
18 miles / 180 minutes
1 mile / 10 minutes
it takes austin to run 10 minutes to run 1 mile
now, we will multiply the number of minutes it takes by 6 to find how long it takes austin to run 6 miles.
1 mile / 10 minutes
6 miles / 60 minutes
it takes austin 60 minutes to run 6 miles
137 paquetes de vasos, aunque el último nomas contiene 7 vasos se necesita el paquete para que no queden sin empacar
