Answer:
- 2(L +W) ≤ 600
- W ≤ 200
- L ≥ 2W
Step-by-step explanation:
We assume the problem wording means the length is to be at least 2 times <em>as long as</em> the width. (<em>Longer than</em> usually refers to a difference, not a scale factor.)
If we let "W" and "L" represent the width and length, respectively, then we can translate the problem statement to ...
2(L + W) ≤ 600 . . . . . . the perimeter is twice the sum of length and width
W ≤ 200 . . . . . . . . . . . . the width is at most 200 inches
L ≥ 2W . . . . . . . . . . . . . the length is at least twice the width
Answer:
Factor by which kinetic energy increase = 4 times
Step-by-step explanation:
Given,
- Mass of the car, v1 = 1500 kg
- initial speed of car = 35 miles/h
= 15.64 m/s
Initial kinetic energy of the car is given by,
= 183606.46 J
- Final velocity of car v2 = 70 miles/hour
= 31.29 m/s
So, final kinetic energy of car is given by
= 734425.84 J
Now, the ratio of final to initial kinetic energy can be given by,
Hence, the kinetic energy will increase by 4 times.
Answer:
since the rate at which concentration inside the cell is proportional to the difference in the concentration of the solute in the blood stream and the concentration within the cell, then the rate of change of concentration within the cell is equals to K(L-C).
Thus, the required differential equation is Δc/Δt = K( L - C ).
Step-by-step explanation: