Answer:
In bold.
Step-by-step explanation:
a. (x+5)^2 – 3x(x+5) x+5 is common
= (x + 5)(x + 5 - 3x)
= (x + 5)(5 - 2x)
b. (x + 5)(5 - 2x) = 0
x = -5, 2.5.
2a. Area of the square = (x + 5)^2
Area of triangle AEB
= 1/2 * base * height
I am assuming that H is the centre of AB , so
Area = x*x
= x^2.
2b
6x^2 = (x + 5)^2
6x^2 = x^2 + 10x + 25
5x^2 - 10x - 25 = 0
x^2 - 2x - 5 = 0
x = [-(-2) +/- sqrt(2^2 - 4*1*-5)] / 2
x = -1.45, 3.45.
(we ignore the negative).
The answer's D. 35/22
Well i have to write 20 words so dont mind this part
Answer:
Angles in right triangles must have measures between 0 and 90°. Angles of rotation can be any real number, which includes negative as well as positive values.
Step-by-step explanation:
Answer on E2020
Answer:
the answer is x=3
Step-by-step explanation:
-3x=1-7
-3x=-6
-x=-6+3
-x=-3
x=3
