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WINSTONCH [101]
3 years ago
9

0.5 is a rational number. True False

Mathematics
2 answers:
velikii [3]3 years ago
5 0

Answer:

true

Step-by-step explanation:

Natural numbers are numbers naturally occurring in nature like 1, 2, 3, 4, 5, 6, 7, 8, 9 . . .

Whole numbers are numbers that are whole, like 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 . . . (the only difference is that there is a 0 included)

Integers include negative and positive numbers like -3, -2, -1, 0, 1, 2, 3, 4 . . .

Rational numbers are include all of the above AND anything that can be turned into a fraction, like fractions and decimals (that have an end) like 0.625, -0.5, 1, 4, 1/4, 6/15, 4.8, etc.

So in this case, yes, 0.5 is a rational number.

egoroff_w [7]3 years ago
3 0

Answer:

true

Step-by-step explanation:

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4 0
3 years ago
The function Q(x)=2x^2-kx+18. For what value of k does Q(x) have one distinct real solution? (NEEDS TO BE DONE WITHIN 2 HOURS!)
Aliun [14]

Answer:

k = 12

Step-by-step explanation:

Given:

The equation Q(x)=2x^2-kx+18

To find:

Value of k = ? for which the given equation has one distinct real solution.

Solution:

The given equation is a quadratic equation.

There are always two solutions of a quadratic equation.

For the equation: ax^{2} +bx+c=0 to have one distinct solution:

b^2 - 4ac = 0

Here,

a = 2,

b = -k and

c = 18

Putting the values, we get:

(-k)^2 - 4\times 2\times 18 = 0\\\Rightarrow k^2 = 18\times 8\\\Rightarrow k^2 =144\\\Rightarrow k = 12

The equation becomes:

Q(x)=2x^2-12x+18

And the one root is:

2(x^2-6x+9 ) = 0\\\Rightarrow 2(x-3)^2=0\\\Rightarrow x = 3

4 0
2 years ago
What is 3x² + 3x - 36 and x² - 3x - 28 in factored form?
satela [25.4K]

Answer:

3x² + 3x - 36=

(3x+12)(x-3)

x² - 3x - 28=

(x+4)(x-7)

Step-by-step explanation:

For both equations use the method called the "Cross Method". It is useful for these type of factorisation questions called "Trinomials".

For more info on the cross method.

Here it is:

https://www.mathsteacher.com.au/year10/ch10_factorisation/05_cross_mult_method/cross.htm

Hope you enjoyed :D

3 0
3 years ago
Read 2 more answers
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