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3 years ago

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There are 2 cubes that are numbered 1 through 6. During a game, both are rolled and the faces landing up are added. How many way

s can a person playing the game roll a sum less than 8

1 answer:

den301095 [7]3 years ago

7 0

I count 5. There could be more. Sorry. Don't have scratch paper at the moment.

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What is -7 + -9 A. -16 B. -2 C. 2 D. 16

nataly862011 [7]

Answer:

is A. -16

Step-by-step explanation:

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2 years ago

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John has two open packs of paper. One pack has 31 pieces of paper. The second pack has 45 pieces of paper. How many pieces of pa

Tems11 [23]

D 76 pieces of paper. Just add

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3 years ago

One three and six are traingular list all the other triangular numbers up to 36

ArbitrLikvidat [17]

That isn’t a question it is a statement

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3 years ago

agasfer [191]

Ok im not sure the answer yet so ima work on it at the same time while im explaining it. (The answer will probably be near the end)

We can use the elimination method to eliminate y out. To do that we multiply the first equation by 3.

6x+3y=-12

Now just subtract it from the other equation.

6x+3y=-12
5x+3y=-6

***x=-6***

Usually after doing the elimination method you will have to solve for x but in this case its already solved for you. If you want to find y now you just take the first equation and fill x with -6 and solve for y.

2(-6)+y=-4
-12+y=-4
y=8

Brainliest my answer if it helps you out?

4 0

3 years ago

Read 2 more answers

The population of a city in 2000 was 500,000 while the population of the suburbs of that city in 2000 was 700,000. Suppose that

Mnenie [13.5K]

Answer:

The population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

Step-by-step explanation:

6% of the city's population moves to the suburbs (and 94% stays in the city).
2% of the suburban population moves to the city (and 98% remains in the suburbs).

The migration matrix is given as:

$A= \left \begin{array}{cc} \\ C \\S \end{array} \right\left[ \begin{array}{cc} C&S\\ 0.94&0.06 \\0.02&0.98 \end{array} \right]$

The population in the year 2000 (initial state) is given as:

$\left[ \begin{array}{cc} C&S\\ 500,000&700,000 \end{array} \right]$

Therefore, the population of the city and the suburb in 2002 (two years after) is:

$S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\& \end{array} \right\left \begin{array}{cc} \end{array} \right\left[ \begin{array}{cc} 0.94&0.06 \\0.02&0.98 \end{array} \right]^2$

$A^{2} = \left[ \begin{array}{cc} 0.8848 & 0.1152 \\\\ 0.0384 & 0.9616 \end{array} \right]$

Therefore:

$S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\& \end{array} \right\left \begin{array}{cc} \end{array} \right \left[ \begin{array}{cc} 0.8848 & 0.1152 \\ 0.0384 & 0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 500,000*0.8848+700,000*0.0384& 500,000*0.1152 +700,000*0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 469280& 730720 \end{array} \right]$

Therefore, the population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

6 0

3 years ago