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blagie [28]
3 years ago
7

Use the equation y= -2+1. complete each problem(0,_)      (-5,_)      (20,_)      (-68,_)

Mathematics
1 answer:
solniwko [45]3 years ago
4 0
1, 11, -39, 137 using the formula
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Which of the following is a polynomial with roots negative square root of 5, square root of 5, and 3? (1 point)
m_a_m_a [10]

The polynomial with roots negative square root of 5, square root of 5, and 3 is Option (C) x^{3} - 3x^{2} -5x +15 = 0 .

In the above question, it is given that  a polynomial with roots negative square root of 5, square root of 5, and 3

=> α = -\sqrt{5}

β = \sqrt{5}

ω = 3

We need to find the polynomial which can be made using the given roots of the polynomial

We know that, a cubic polynomial can be formed with the help of given roots as following

x^{3} - ( α+β+ω)x^{2} + (αβ+βω + αω)x - (αβω) = 0

So, first we'll find,

Sum of roots = α+β+ω = -\sqrt{5}+ \sqrt{5} + 3 = 3

Product of two roots at a time = αβ+βω + αω = -\sqrt{5}\sqrt{5} + -\sqrt{5}.3 + 3.-\sqrt{5} =

-5 + 3\sqrt{5} -3\sqrt{5} =  -5

Product of roots = αβω = -\sqrt{5} . \sqrt{5} . 3 = -15

Now putting all the values in the polynomial equation, we get

x^{3} - ( α+β+ω)x^{2} + (αβ+βω + αω)x - (αβω) = 0

x^{3} - ( 3)x^{2} + (-5 )x - (-15) = 0

x^{3} - 3x^{2} + (-5 )x - (-15) = 0

x^{3} - 3x^{2} -5x +15 = 0

Hence, the polynomial with roots negative square root of 5, square root of 5, and 3 is x^{3} - 3x^{2} -5x +15 = 0 .

To learn more about, cubic polynomial, here

brainly.com/question/28081769

#SPJ1

7 0
1 year ago
A student wrote and simplified an expression for the perimeter of the rectangle. (Using the picture provided.)
muminat

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Step-by-step explanation:

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The weight y of an object on Mars is proportional to the weight x of the object on Earth. An object that weighs 70 pounds on Ear
Zarrin [17]
70/28 = x/250
this however is not an equation it is a proportion so you would not be able to solve using systems of equations but you could use cross multiplication to solve this problem as well
4 0
4 years ago
A company that makes pencils realized that 2 out of every 25 pencils were defective. How many pencils out of 200 will be defecti
levacccp [35]
2 X
— • — Cross multiply
25 200


25x 400
—— —— Divide
25 25

16


Out of 200, 16 pencils will be defective
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Let sin A = -3/5<br> with 270° sinA/2
Solnce55 [7]

Answer:

-0.316227766

Step-by-step explanation:

0.316227766

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