Question

Nathaniel builds birds and birdhouses using Lego blocks. Let B represent the number of birds and H represent the number of birdhouses that Nathaniel can build with his Lego blocks. 43B + 215H? 3000 Nathaniel wants to build 50 birds using Lego blocks. How many birdhouses can he build at most with the remaining Lego blocks?

Answer 1

Answer:

3 birdhouses

Step-by-step explanation:

Answer 2

Answer:

At-most 3 birdhouses.

Step-by-step explanation:

Let B represent the number of birds and H represent the number of birdhouses that Nathaniel can build with his Lego blocks.

We have been given that Nathaniel builds birds and birdhouses using Lego blocks. The inequality $43B+215H\leq3000$ represents the number of birds and birdhouses Nathaniel could build.

To find the number of birdhouses that Nathaniel can build after making 50 birds, we will substitute B=50 in our given inequality and then solve for H.

$43*50+215H\leq3000$

$2150+215H\leq3000$

Let us subtract 2150 from both sides of our inequality.

$2150-2150+215H\leq3000-2150$

$215H\leq850$

Let us divide both both sides of our inequality by 215.

$\frac{215H}{215}\leq\frac{850}{215}$

$H\leq3.953488$

As Nathaniel can make build less than or equal to 3.953488 and the biggest integer less than or equal to 3.953 is 3, therefore, Nathaniel can build at-most 3 birdhouses with remaining Lego blocks.