Nathaniel builds birds and birdhouses using Lego blocks. Let B represent the number of birds and H represent the number of birdh
ouses that Nathaniel can build with his Lego blocks. 43B + 215H? 3000 Nathaniel wants to build 50 birds using Lego blocks. How many birdhouses can he build at most with the remaining Lego blocks?
2 answers:
Answer:
At-most 3 birdhouses.
Step-by-step explanation:
Let B represent the number of birds and H represent the number of birdhouses that Nathaniel can build with his Lego blocks.
We have been given that Nathaniel builds birds and birdhouses using Lego blocks. The inequality represents the number of birds and birdhouses Nathaniel could build.
To find the number of birdhouses that Nathaniel can build after making 50 birds, we will substitute B=50 in our given inequality and then solve for H.
Let us subtract 2150 from both sides of our inequality.
Let us divide both both sides of our inequality by 215.
As Nathaniel can make build less than or equal to 3.953488 and the biggest integer less than or equal to 3.953 is 3, therefore, Nathaniel can build at-most 3 birdhouses with remaining Lego blocks.
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Answer:
The probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.
Step-by-step explanation:
Let <em>X</em> = number of individuals in the United States who held multiple jobs.
The probability that an individual holds multiple jobs is, <em>p</em> = 0.13.
The sample of employed individuals selected is of size, <em>n</em> = 225.
An individual holding multiple jobs is independent of the others.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 225 and <em>p</em> = 0.13.
But since the sample size is too large Normal approximation to Binomial can be used to define the distribution of proportion <em>p</em>.
Conditions of Normal approximation to Binomial are:
- np ≥ 10
- n (1 - p) ≥ 10
Check the conditions as follows:
The distribution of the proportion of individuals who hold multiple jobs is,
Compute the probability that less than 7.1% of the individuals in this sample hold multiple jobs as follows:
*Use a <em>z</em>-table.
Thus, the probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.