There is no P in here, you can't solve for P without a P, Or I just don't get the question.
Answer:
A dozen = 12
Step-by-step explanation:
I think I’m right
Answer: (x - 4)(x - (i))(x + (i))
Step-by-step explanation:
This factoring job lends itself well to synthetic division. Looking at the constant term, -4, I came up with several possible roots based upon -4: {±1, ±2, ±4}. I chose +4 as my first trial root. Sure enough, there was a zero remainder, which indicated that 4 is a root of this polynomial and (x - 4) is a factor. The coefficients of the trinomial quotients are 1 0 1, which indicates a quotient of x^2 + 1, which has the following roots: x = +(i) and x = -(i)
So the complete factorization of the polynomial is (x - 4)(x - (i))(x + (i)).
4 ) 1 -4 1 -4
----------------------
Answer:
1
Answer:
1) 0.5
2)-2
3)-23
Step-by-step explanation:
1) -3×1=-3
-3+2.5= 0.5
2) -3×1.5=-4.5
-4.5+2.5= -2
3) -3×8.5=-25.5
-25.5+2.5=-23