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xxMikexx [17]
3 years ago
13

A cylindrical barrel has a diameter of 19.875 inches. Which of the following is the bestestimate of the circumference of the bar

rel in feet?
Mathematics
1 answer:
sveticcg [70]3 years ago
8 0
Alright we know the formula for circumfruence is 2\pir

So you plug it in!
Note: Radius is just the diameter split in half.

2*3.14*9.9375

2*31.20375

So the circumference of the barrel is 62.4075
You might be interested in
A model railway train is designed using a scale factor of 1:87. If the model train is 4 inches , how many feet long is the actua
goblinko [34]

Answer:

The actual length of the train is 79 3/4 feet

Step-by-step explanation:

5 0
3 years ago
an organic form uses 3/7 of the land to grow potatoes and 2/5 of the land to grow spinach. The remaining land is used to grow to
zheka24 [161]
1/37 of land is used to grow tomatoes.
7 0
3 years ago
Solve for x and y<br> 1.45 x + 1.55y = 20 and x + y = 29.80
Igoryamba
X+y=29.8
Y=29.8-x so
1.45x+1.55(29.8-x)=20 then solve for x
1.45x+46.19-1.55x=20
-0.1x=20-46.19
-0.1x=−26.19
X=26.19/0.1
X=261.9
Y=29.8-261.9
Y=−232
3 0
3 years ago
Can yall help meh thanks​
amm1812

Answer:

1/2 = 3/6 so if

1/2 + 1/6 = 3/6+1/6 = 4/6

to reduce 4/6, divide top and bottom by same number, in this case, 2.

4/6 = 2/3

3 0
3 years ago
A sample of 500 people are asked,"If you could have a new vehicle, would you want asport utility vehicle or a car?" The result o
kykrilka [37]

The complete table would be the follwing:

A.

To get this probability, we take the total number people who pefer an SUV, and divide it by the total number of people in the sample

P(S)=\frac{210}{500}

B.

To get this probability, we take the total number of females, and divide it by the total number of people in the sample

P(F)=\frac{315}{500}

C.

To get this probability, we take the total number of females who pefer a car, and divide it by the total number of people in the sample

P(F\cap C)=\frac{263}{500}

D.

\begin{gathered} P(F\cup S)=P(F)+P(S)-P(F\cap S) \\ \rightarrow P(F\cup S)=\frac{315}{500}+\frac{210}{500}-\frac{52}{500} \\  \\ \Rightarrow P(F\cup S)=\frac{473}{500} \end{gathered}

E.

\begin{gathered} P(S|M)=\frac{P(S\cap M)}{P(S)} \\  \\ \rightarrow P(S|M)=\frac{\frac{158}{500}}{\frac{210}{500}} \\  \\ \Rightarrow P(S|M)=\frac{158}{210} \end{gathered}

F.

\begin{gathered} P(M|S)=\frac{P(M\cap S)}{P(S)} \\  \\ \rightarrow P(M|S)=\frac{\frac{158}{500}}{\frac{185}{500}} \\  \\ \Rightarrow P(M|S)=\frac{158}{185} \end{gathered}

In the final question we're being asked for:

P((M\cap S)\cap(M\cap C))

This is:

P(M\cap S)\cdot P(M\cap C)\frac{158}{500}\cdot\frac{27}{500}=0.017

Therefore, this probability is 0.017

8 0
1 year ago
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