Answer:
method 1: find l. c. m of 13/15 and 5/6
<h2>26, 25/30</h2><h3>
<em>fraction </em><em>that </em><em>have</em><em> </em><em>26,</em><em> </em><em>and </em><em>25 </em><em>are </em><em>13/</em><em>1</em><em>5</em><em> </em><em>and </em><em>5/</em><em>6</em><em> </em><em>respectively</em><em>. </em></h3><h3>
<em>therefor</em><em>e</em><em>:</em><em> </em><em>13/</em><em>1</em><em>5</em><em>›</em><em>5</em><em>÷</em><em>/</em><em>6</em><em> </em><em>or </em><em>5</em><em>/</em><em>6</em><em>‹</em><em>1</em><em>3</em><em>/</em><em>1</em><em>5</em></h3>
It depends on what did you mean by saying perfect square. If I've understood it correctly, I can help you with a part of your problem. The squares of mod <span>9</span><span> are </span><span><span>1</span><span>,4,7</span></span><span> which are came from </span><span><span>1,2,</span><span>4.</span></span><span> </span>Addition of the given numbers are 2,3,5,6, 8, which are exactly the part of your problem. This number, which is not shown as squares Mod 9, and thus doesn't appear as a sum of digits of a perfect square. I hope you will find it helpful.
Answer:
You do -17 + -10 inorder to change the operation used because both negatives does not mathematically look nice.
Step-by-step explanation:
To isolate the unknown, we need to move all the numbers on one side of the equal sign and all the unknow variables on one side.
Here we move 10 on the other side by taking away 10 both sides
10 + 3x = -17
-10 -10
then we are left with only 3x on one side and -27 on the other side because -17 - -10 = -27 , in this case it is acknowledge to change the operation from minus to add because the two minus are together, so we say -17 + -10 .
3x = -27
/3 /3
x = -9
Answer:
(5,8) over y axis and (-5,-8) over x axis
Step-by-step explanation:
to find the sum:
2(3t-4) - (t^2 + 2) - 4t(t-1)
6t - 8 - t^2 - 2 - 4t^2 + 4
6t - 8 - 5t^2 + 2
-5t^2 + 6t - 6
by the sum of roots and product of roots formulae
ax^2 + bx + c
x + y = 
x + y = 
xy = 
xy = 
x - y =