Answer:
Option C. f(n) = 16(3/2)⁽ⁿ¯¹⁾
Step-by-step explanation:
To know which option is correct, do the following:
For Option A
f(n) = 3/2(n – 1) + 16
n = 1
f(n) = 3/2(1 – 1) + 16
f(n) = 3/2(0) + 16
f(n) = 16
n = 2
f(n) = 3/2(n – 1) + 16
f(n) = 3/2(2 – 1) + 16
f(n) = 3/2(1) + 16
f(n) = 3/2 + 16
f(n) = 1.5 + 16
f(n) = 17.5
For Option B
f(n) = 3/2(16)⁽ⁿ¯¹⁾
n = 1
f(n) = 3/2(16)⁽¹¯¹⁾
f(n) = 3/2(16)⁰
f(n) = 3/2 × 1
f(n) = 1
For Option C
f(n) = 16(3/2)⁽ⁿ¯¹⁾
n = 1
f(n) = 16(3/2)⁽¹¯¹⁾
f(n) = 16(3/2)⁰
f(n) = 16 × 1
f(n) = 16
n = 2
f(n) = 16(3/2)⁽ⁿ¯¹⁾
f(n) = 16(3/2)⁽²¯¹⁾
f(n) = 16(3/2)¹
f(n) = 16(3/2)
f(n) = 8 × 3
f(n) = 24
n = 3
f(n) = 16(3/2)⁽ⁿ¯¹⁾
f(n) = 16(3/2)⁽³¯¹⁾
f(n) = 16(3/2)²
f(n) = 16(9/4)
f(n) = 4 × 9
f(n) = 36
For Option D
f(n) = 8n + 8
n = 1
f(n) = 8(1) + 8
f(n) = 8 + 8
f(n) = 16
n = 2
f(n) = 8n + 8
f(n) = 8(2) + 8
f(n) = 16 + 8
f(n) = 24
n = 3
f(n) = 8n + 8
f(n) = 8(3) + 8
f(n) = 24 + 8
f(n) = 32
From the above illustration, only option C describes the sequence.
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Step-by-step explanation:
mass of the object=m=4 kg
the net force exerted on it=F=24N=kgm/s²
the acceleration of the object=a=?
formula for calculating the acceleration=
F=ma
plug in the values
24kgm/s²=4kga
divide each side by 4
24kgm/s²/4 kg=4kga/4kg
a=6m/s²
