The number of possible combinations is given by
... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations
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There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.
Do this.
38 divided by two
then use the equation
38=5+2x
Answer:
I'm not sure what the answer choices are but that would seem like a piece of sketch paper.
Step-by-step explanation:
35/6
= how many times can (6) go into (35)? 5 TIMES.
Remainder (5)
So as a mixed number would be 5 whole number, 5/6.
(5 5/6)
