3 years ago

Whhhhhhaaaaa ? Helppppp

Mathematics

1 answer:

tino4ka555 [31]3 years ago

4 0

Median= 45.5
UQ= 49
LQ= 35
IQR= 14

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Judy hiked on two trails. The first trail was 5- 1/4 miles long, and the second trail was 1- 1/2 times longer than the first one

scoundrel [369]

Answer:

Judy hiked: $1\frac{37}{68} miles$

Step-by-step explanation:

The first trail = $5\frac{1}{4}= \frac{21}{4}$ miles

The second trail = 1 1/2 times longer than the first

$1\frac{1}{2} * 5\frac{1}{4}\\\\ = \frac{3}{2}*\frac{21}{4} =\frac{63}{8}$ miles

Total trails then becomes:

$\frac{21}{4} +\frac{63}{8}= \frac{(2*21) + 63}{8} \\\\= \frac{42+63}{68}=\frac{105}{68} \\\\= 1\frac{37}{68} miles$

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3 years ago

The volume V of a fixed amount of a gas varies directly as the temperature T and inversely as the pressure P. Suppose that V=160

dsp73

Answer:

Volume = 90 cm³

Step-by-step explanation:

Given:

The volume 'V' of a fixed amount of gas is directly proportional to the temperature 'T' and inversely proportional to the pressure 'P'.

Initial volume is, $V_1=160\ cm^3$

Initial temperature is, $T_1=320\ K$

Initial pressure is, $P_1=12\ kg/cm^2$

Final temperature is, $T_2=240\ K$

Final pressure is, $P_2=16\ kg/cm^2$

Final volume is, $V_2=?$

As per question:

$V\propto\frac{T}{P}$

Therefore,

$\frac{PV}{T}=Constant$

Or, we can write the above as:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\\\\\frac{12\times 160}{320}=\frac{16\times V_1}{240}\\\\6=\frac{V_1}{15}\\\\V_1=15\times 6=90\ cm^3$

Therefore, the final volume is 90 cm³.

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There are 99 gold balls

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Greg is recording the changes in his bank account balance. In the morning, he records a deposit of $7. In the afternoon, he reco

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Step-by-step explanation:

i think that it is either -7 - -8 or -7 + 8 or -7+-8.

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What is 2,722 round to the nearest thousand

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2,000.....................

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