The equation is
P = 200 / (1 + 20000 e^-0.549t)
TO get the rate of epidemic growth, we differentiate the equation with respect to t
dP/dt = -200(1 + 2000 e^-0.549t)^-2 (20000)(-0.549)
Substitute t = 10 and you will get the epidemic growth rate after 10 years
Answer:
A. and C.
if you simplify the expressions, you will see which ones are equal to the expression given
The equation is already solved for you basically
Answer:
< > > I am pretty sure that is it
Answer:
The answer is A). I took the test on usatestprep
Step-by-step explanation:
